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Question 913 of 949

A car travels 150 kilometers east in 2 hours and then 50 kilometers west in 1 hour. What is the average velocity of the car for the entire trip?

  • 50 km/h east
  • 100 km/h east
  • 33.33 km/h east
  • 50 km/h west

Correct Answer: A

Explanation
To determine the average velocity of the car for the entire trip, we need to follow a systematic approach. Let's break it down step-by-step. ### Step 1: Understand the Concept of Average Velocity Average velocity is defined as the total displacement divided by the total time taken. Displacement is the straight-line distance from the starting point to the final position, along with the direction. ### Step 2: Calculate Total Displacement 1. **First Leg of the Trip**: The car travels 150 kilometers east. - Displacement = +150 km (east is considered positive) 2. **Second Leg of the Trip**: The car then travels 50 kilometers west. - Displacement = -50 km (west is considered negative) 3. **Total Displacement**: \[ \text{Total Displacement} = 150 \text{ km (east)} - 50 \text{ km (west)} = 150 \text{ km} - 50 \text{ km} = 100 \text{ km (east)} \] ### Step 3: Calculate Total Time 1. **Time for the First Leg**: 2 hours 2. **Time for the Second Leg**: 1 hour 3. **Total Time**: \[ \text{Total Time} = 2 \text{ hours} + 1 \text{ hour} = 3 \text{ hours} \] ### Step 4: Calculate Average Velocity Now that we have both total displacement and total time, we can calculate the average velocity using the formula: \[ \text{Average Velocity} = \frac{\text{Total Displacement}}{\text{Total Time}} \] Substituting the values we calculated: \[ \text{Average Velocity} = \frac{100 \text{ km (east)}}{3 \text{ hours}} \approx 33.33 \text{ km/h (east)} \] ### Conclusion The average velocity of the car for the entire trip is approximately **33.33 km/h east**. Therefore, the correct option is **C**. ### Explanation of Other Options - **Option A (50 km/h east)**: This option is incorrect because it does not take into account the total displacement and time correctly. The average velocity is not simply the average of the two speeds. - **Option B (100 km/h east)**: This option is incorrect as it suggests that the car traveled 100 km in 1 hour, which is not the case. The total distance traveled is not the same as the displacement. - **Option D (50 km/h west)**: This option is incorrect because it misrepresents the direction of the average velocity. The net displacement is east, not west. ### Common Pitfalls - Confusing distance with displacement: Remember that distance is the total path traveled, while displacement is the straight-line distance from start to finish. - Not considering direction: Average velocity is a vector quantity, so direction matters. - Miscalculating total time or displacement can lead to incorrect average velocity. ### Revision Summary - Average velocity = Total displacement / Total time. - Displacement considers direction; distance does not. - For this problem, total displacement = 100 km east, total time = 3 hours. - Average velocity = 33.33 km/h east (Option C is correct).
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