Question 912 of 949
An object is moving in a straight line with a constant acceleration of 2 m/s². If its initial velocity is 5 m/s, what will be its velocity after 4 seconds?
- 13 m/s
- 17 m/s
- 9 m/s
- 21 m/s
Correct Answer:
A
Explanation
To find the velocity of an object moving with constant acceleration, we can use the following kinematic equation:
\[ v = u + at \]
Where:
- \( v \) = final velocity (what we want to find)
- \( u \) = initial velocity
- \( a \) = acceleration
- \( t \) = time
### Step-by-Step Solution
1. **Identify the given values**:
- Initial velocity (\( u \)) = 5 m/s
- Acceleration (\( a \)) = 2 m/s²
- Time (\( t \)) = 4 seconds
2. **Substitute the values into the equation**:
\[
v = 5 \, \text{m/s} + (2 \, \text{m/s}^2 \times 4 \, \text{s})
\]
3. **Calculate the acceleration component**:
\[
2 \, \text{m/s}^2 \times 4 \, \text{s} = 8 \, \text{m/s}
\]
4. **Add this to the initial velocity**:
\[
v = 5 \, \text{m/s} + 8 \, \text{m/s} = 13 \, \text{m/s}
\]
Thus, the final velocity after 4 seconds is **13 m/s**.
### Conclusion
The correct option is **A. 13 m/s**.
### Explanation of Other Options
- **B. 17 m/s**: This option is incorrect because it suggests an additional 4 m/s of velocity that does not come from the given acceleration over the specified time.
- **C. 9 m/s**: This option is also incorrect. It implies a decrease in velocity, which contradicts the effect of positive acceleration acting on the object.
- **D. 21 m/s**: This option is incorrect as it suggests an overestimation of the final velocity, likely due to a miscalculation of the acceleration component.
### Common Pitfalls
- **Misunderstanding acceleration**: Remember that acceleration is the rate of change of velocity. If the acceleration is positive, the final velocity will always be greater than the initial velocity if time is positive.
- **Forgetting to multiply acceleration by time**: Always ensure to multiply the acceleration by the time duration to find the total change in velocity.
- **Confusing units**: Ensure that all units are consistent (e.g., m/s for velocity and m/s² for acceleration).
### Revision Summary
- Use the formula \( v = u + at \) to find final velocity.
- Substitute initial velocity, acceleration, and time correctly.
- Calculate the change in velocity due to acceleration accurately.
- Check your final answer against the options provided to ensure it matches.