Question 917 of 949
A 5 kg box is resting on a horizontal surface. If the coefficient of static friction between the box and the surface is 0.4, what is the maximum static friction force that can act on the box before it starts to move?
Correct Answer:
B
Explanation
To determine the maximum static friction force that can act on a 5 kg box resting on a horizontal surface with a coefficient of static friction of 0.4, we can use the formula for static friction:
### Step 1: Understand the Formula
The maximum static friction force (\(F_{s, \text{max}}\)) can be calculated using the formula:
\[
F_{s, \text{max}} = \mu_s \cdot F_N
\]
Where:
- \(F_{s, \text{max}}\) is the maximum static friction force.
- \(\mu_s\) is the coefficient of static friction.
- \(F_N\) is the normal force acting on the box.
### Step 2: Calculate the Normal Force
For an object resting on a horizontal surface, the normal force (\(F_N\)) is equal to the weight of the object. The weight can be calculated using the formula:
\[
F_N = m \cdot g
\]
Where:
- \(m\) is the mass of the box (5 kg).
- \(g\) is the acceleration due to gravity (approximately \(9.81 \, \text{m/s}^2\)).
Calculating the normal force:
\[
F_N = 5 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 = 49.05 \, \text{N}
\]
### Step 3: Calculate the Maximum Static Friction Force
Now, we can substitute the values into the static friction formula:
\[
F_{s, \text{max}} = \mu_s \cdot F_N = 0.4 \cdot 49.05 \, \text{N}
\]
Calculating this gives:
\[
F_{s, \text{max}} = 0.4 \cdot 49.05 \approx 19.62 \, \text{N}
\]
### Step 4: Rounding and Selecting the Correct Option
Since the options provided are whole numbers, we can round \(19.62 \, \text{N}\) to \(20 \, \text{N}\). Therefore, the maximum static friction force that can act on the box before it starts to move is:
**Correct Option: B. 20 N**
### Step 5: Explanation of Other Options
- **Option A (10 N)**: This value is too low. It does not take into account the mass of the box and the gravitational force acting on it.
- **Option C (25 N)**: This value is higher than the calculated maximum static friction force. It suggests a higher coefficient of friction or a greater normal force than what is present in this scenario.
- **Option D (50 N)**: This value is also too high. It would imply a coefficient of static friction of 1.02, which is unrealistic for most materials in contact.
### Common Pitfalls
- **Ignoring the Normal Force**: Always remember that the normal force is crucial in calculating friction. It is not always equal to the weight, especially on inclined surfaces.
- **Misunderstanding Coefficients**: The coefficient of static friction is a ratio and should be multiplied by the normal force to find the maximum static friction force.
- **Rounding Errors**: Be careful with rounding; always keep significant figures in mind until the final answer.
### Revision Summary
- The maximum static friction force is calculated using \(F_{s, \text{max}} = \mu_s \cdot F_N\).
- The normal force for a horizontal surface is equal to the weight of the object.
- For a 5 kg box with \(\mu_s = 0.4\), the maximum static friction force is approximately 20 N.
- Always check the reasonableness of your answer against the options provided.