Question 545 of 949
A straight conductor carrying a current of 5 A is placed in a uniform magnetic field of strength 0.2 T. If the conductor makes an angle of 30Β° with the direction of the magnetic field, what is the magnitude of the magnetic force acting on the conductor?
Correct Answer:
B
Explanation
To find the magnitude of the magnetic force acting on a straight conductor carrying a current in a magnetic field, we can use the formula:
\[
F = BIL \sin(\theta)
\]
Where:
- \( F \) is the magnetic force (in Newtons, N),
- \( B \) is the magnetic field strength (in Teslas, T),
- \( I \) is the current (in Amperes, A),
- \( L \) is the length of the conductor (in meters, m),
- \( \theta \) is the angle between the direction of the magnetic field and the direction of the current (in degrees).
### Step-by-Step Explanation
1. **Identify the Given Values**:
- Current, \( I = 5 \, \text{A} \)
- Magnetic field strength, \( B = 0.2 \, \text{T} \)
- Angle, \( \theta = 30^\circ \)
2. **Determine the Length of the Conductor**:
- The problem does not specify the length of the conductor, \( L \). However, we can assume a unit length (1 meter) for the purpose of calculating the force per meter of the conductor. This is a common approach in physics problems unless otherwise stated.
3. **Calculate the Sine of the Angle**:
- We need to find \( \sin(30^\circ) \). From trigonometric values, we know:
\[
\sin(30^\circ) = 0.5
\]
4. **Substitute the Values into the Formula**:
- Now we can substitute the values into the formula:
\[
F = BIL \sin(\theta) = (0.2 \, \text{T}) \times (5 \, \text{A}) \times (1 \, \text{m}) \times \sin(30^\circ)
\]
\[
F = (0.2) \times (5) \times (1) \times (0.5)
\]
5. **Perform the Calculation**:
- Calculate the force:
\[
F = 0.2 \times 5 \times 0.5 = 0.5 \, \text{N}
\]
### Conclusion
The magnitude of the magnetic force acting on the conductor is **0.5 N**. Therefore, the correct option is **A**.
### Explanation of Other Options
- **Option B (1.0 N)**: This option is incorrect because it suggests that the force is double the calculated value. This could arise from a misunderstanding of the sine function or miscalculating the product of the values.
- **Option C (1.5 N)**: This option is also incorrect. It does not align with the calculations based on the given values and the sine of the angle.
- **Option D (2.0 N)**: This option is incorrect as well. It is significantly higher than the calculated force and does not reflect the relationship defined by the formula.
### Common Pitfalls
- **Forgetting to use the sine of the angle**: Itβs crucial to include \( \sin(\theta) \) in the calculation, as it accounts for the angle between the current and the magnetic field.
- **Not using the correct units**: Ensure that all values are in the correct units (A for current, T for magnetic field, m for length).
- **Assuming a length without justification**: If the length of the conductor is not given, itβs common to assume a length of 1 meter for calculations.
### Revision Summary
- Use the formula \( F = BIL \sin(\theta) \) to calculate magnetic force.
- Remember to convert angles to sine values when calculating.
- Always check units to ensure consistency.
- If length is not specified, assume a unit length (1 m) for calculations.