Question 544 of 949
A straight conductor carrying a current of 5 A is placed in a uniform magnetic field of strength 0.2 T. If the length of the conductor within the magnetic field is 0.4 m and the angle between the conductor and the magnetic field is 90 degrees, what is the magnitude of the magnetic force acting on the conductor?
Correct Answer:
C
Explanation
To determine the magnitude of the magnetic force acting on a straight conductor carrying a current in a magnetic field, we can use the formula:
\[
F = BIL \sin(\theta)
\]
Where:
- \( F \) is the magnetic force (in Newtons, N),
- \( B \) is the magnetic field strength (in Teslas, T),
- \( I \) is the current (in Amperes, A),
- \( L \) is the length of the conductor within the magnetic field (in meters, m),
- \( \theta \) is the angle between the conductor and the magnetic field (in degrees or radians).
### Given Data:
- Current, \( I = 5 \, \text{A} \)
- Magnetic field strength, \( B = 0.2 \, \text{T} \)
- Length of the conductor, \( L = 0.4 \, \text{m} \)
- Angle, \( \theta = 90^\circ \)
### Step-by-Step Calculation:
1. **Identify the sine of the angle**: Since the angle \( \theta \) is \( 90^\circ \), we know that:
\[
\sin(90^\circ) = 1
\]
2. **Substitute the values into the formula**:
\[
F = BIL \sin(\theta) = (0.2 \, \text{T}) \times (5 \, \text{A}) \times (0.4 \, \text{m}) \times 1
\]
3. **Perform the multiplication**:
- First, calculate \( B \times I \):
\[
0.2 \, \text{T} \times 5 \, \text{A} = 1.0 \, \text{T} \cdot \text{A}
\]
- Next, multiply by \( L \):
\[
1.0 \, \text{T} \cdot \text{A} \times 0.4 \, \text{m} = 0.4 \, \text{N}
\]
4. **Final Result**:
\[
F = 0.4 \, \text{N}
\]
### Conclusion:
The magnitude of the magnetic force acting on the conductor is **0.4 N**. Therefore, the correct option is **A**.
### Explanation of Other Options:
- **Option B (1.0 N)**: This value could be mistakenly calculated if one were to incorrectly multiply the values or misinterpret the angle. However, it does not match our calculations.
- **Option C (2.0 N)**: This option might arise from an error in calculating the product of \( B \), \( I \), and \( L \) or misunderstanding the sine function. It is not supported by the calculations.
- **Option D (4.0 N)**: This option is significantly higher than the calculated force and suggests a misunderstanding of the relationship between the variables or a miscalculation.
### Common Pitfalls:
- Forgetting to convert units or misinterpreting the angle can lead to incorrect results.
- Not recognizing that \( \sin(90^\circ) = 1 \) can lead to unnecessary complications in calculations.
- Confusing the direction of the force with its magnitude; the formula gives magnitude only.
### Revision Summary:
- Use the formula \( F = BIL \sin(\theta) \) to calculate magnetic force.
- Ensure to use the correct values for \( B \), \( I \), \( L \), and \( \theta \).
- Remember that \( \sin(90^\circ) = 1 \) simplifies calculations.
- Check calculations step-by-step to avoid common errors.