Question 549 of 949
A straight conductor carrying a current of 5 A is placed in a uniform magnetic field of strength 0.2 T. If the conductor is oriented perpendicular to the magnetic field, what is the magnetic force acting on a 0.5 m length of the conductor?
Correct Answer:
B
Explanation
To determine the magnetic force acting on a straight conductor carrying a current in a magnetic field, we can use the formula:
\[
F = BIL \sin(\theta)
\]
Where:
- \( F \) is the magnetic force (in Newtons, N),
- \( B \) is the magnetic field strength (in Teslas, T),
- \( I \) is the current (in Amperes, A),
- \( L \) is the length of the conductor (in meters, m),
- \( \theta \) is the angle between the conductor and the magnetic field.
### Step-by-Step Explanation
1. **Identify the Given Values**:
- Current, \( I = 5 \, \text{A} \)
- Magnetic field strength, \( B = 0.2 \, \text{T} \)
- Length of the conductor, \( L = 0.5 \, \text{m} \)
- The angle \( \theta = 90^\circ \) (since the conductor is oriented perpendicular to the magnetic field).
2. **Substituting Values into the Formula**:
Since the conductor is perpendicular to the magnetic field, \( \sin(90^\circ) = 1 \). Therefore, the formula simplifies to:
\[
F = BIL
\]
3. **Calculating the Force**:
Now, substituting the known values into the simplified formula:
\[
F = (0.2 \, \text{T}) \times (5 \, \text{A}) \times (0.5 \, \text{m})
\]
Calculating this step-by-step:
- First, calculate \( B \times I \):
\[
0.2 \, \text{T} \times 5 \, \text{A} = 1.0 \, \text{T} \cdot \text{A}
\]
- Next, multiply by the length \( L \):
\[
1.0 \, \text{T} \cdot \text{A} \times 0.5 \, \text{m} = 0.5 \, \text{N}
\]
Thus, the magnetic force \( F \) acting on the conductor is:
\[
F = 0.5 \, \text{N}
\]
### Conclusion
The correct answer is **A. 0.5 N**.
### Explanation of Other Options
- **Option B (1.0 N)**: This option is incorrect because it assumes either a higher current, a longer length, or a different angle than what was provided. The calculations clearly show that the force is 0.5 N.
- **Option C (1.5 N)**: This option is also incorrect for the same reasons as option B. The values provided do not support a force of 1.5 N.
- **Option D (2.0 N)**: This option is incorrect as well. The calculations do not yield a force of 2.0 N, and it would require either a higher magnetic field strength or a longer conductor length.
### Common Pitfalls
- **Forgetting the Angle**: Always check the angle between the conductor and the magnetic field. If itβs not 90 degrees, you must use the sine function correctly.
- **Units**: Ensure that all units are consistent (e.g., current in Amperes, length in meters, magnetic field in Teslas).
- **Misinterpretation of the Formula**: Remember that the force is directly proportional to the current, magnetic field strength, and length of the conductor.
### Revision Summary
- Use the formula \( F = BIL \sin(\theta) \) to calculate magnetic force.
- Ensure the angle is correctly identified; \( \sin(90^\circ) = 1 \).
- Substitute values carefully and perform calculations step-by-step.
- Check units and ensure they are consistent throughout the calculation.