Question 71 of 480
If y = 2xcos2x - sin2x, find dy/dx when x = π/4
- A. π
- B. -π
- C. π/2
- D. -π/2
Correct Answer:
B
Explanation
To find the derivative \( \frac{dy}{dx} \) of the function \( y = 2x \cos(2x) - \sin(2x) \) and evaluate it at \( x = \frac{\pi}{4} \), we will follow these steps:
### Step 1: Differentiate the function
We need to differentiate \( y \) with respect to \( x \). The function consists of two parts: \( 2x \cos(2x) \) and \( -\sin(2x) \). We will use the product rule for the first part and the chain rule for the second part.
#### Part 1: Differentiate \( 2x \cos(2x) \)
Using the product rule, which states that if \( u = 2x \) and \( v = \cos(2x) \), then:
\[
\frac{d(uv)}{dx} = u \frac{dv}{dx} + v \frac{du}{dx}
\]
- \( u = 2x \) implies \( \frac{du}{dx} = 2 \)
- \( v = \cos(2x) \) implies \( \frac{dv}{dx} = -\sin(2x) \cdot 2 = -2\sin(2x) \) (using the chain rule)
Now applying the product rule:
\[
\frac{d}{dx}(2x \cos(2x)) = 2x(-2\sin(2x)) + \cos(2x)(2) = -4x\sin(2x) + 2\cos(2x)
\]
#### Part 2: Differentiate \( -\sin(2x) \)
Using the chain rule:
\[
\frac{d}{dx}(-\sin(2x)) = -\cos(2x) \cdot 2 = -2\cos(2x)
\]
### Step 2: Combine the derivatives
Now we combine the derivatives from both parts:
\[
\frac{dy}{dx} = (-4x\sin(2x) + 2\cos(2x)) - 2\cos(2x)
\]
This simplifies to:
\[
\frac{dy}{dx} = -4x\sin(2x) + 2\cos(2x) - 2\cos(2x) = -4x\sin(2x)
\]
### Step 3: Evaluate \( \frac{dy}{dx} \) at \( x = \frac{\pi}{4} \)
Now we substitute \( x = \frac{\pi}{4} \) into the derivative:
\[
\frac{dy}{dx} = -4\left(\frac{\pi}{4}\right)\sin\left(2 \cdot \frac{\pi}{4}\right)
\]
Calculating \( 2 \cdot \frac{\pi}{4} = \frac{\pi}{2} \), we find:
\[
\sin\left(\frac{\pi}{2}\right) = 1
\]
Thus, substituting this back into the derivative:
\[
\frac{dy}{dx} = -4\left(\frac{\pi}{4}\right)(1) = -\pi
\]
### Conclusion
The value of \( \frac{dy}{dx} \) when \( x = \frac{\pi}{4} \) is \( -\pi \).
### Final Answer
The correct option is **B. -π**.
### Explanation of Other Options
- **A. π**: This option is incorrect because we derived \( -\pi \), not \( \pi \).
- **C. π/2**: This option is incorrect as it does not match our derived value of \( -\pi \).
- **D. -π/2**: This option is also incorrect because it is not equal to \( -\pi \).
### Revision Summary
- Use the product rule for differentiating products of functions.
- Apply the chain rule for functions within functions.
- Combine derivatives carefully and simplify.
- Evaluate the derivative at the specified point to find the final answer.