Question 202 of 480
Evaluate \(\int_{1}^{3}(x^2 - 1)dx\)
- A. \(\frac{2}{3}\)
- B. \(-\frac{2}{3}\)
- C. \(-6\frac{2}{3}\)
- D. \(6\frac{2}{3}\)
Correct Answer:
D
Explanation
To evaluate the integral \(\int_{1}^{3}(x^2 - 1)dx\), we will follow a step-by-step approach.
### Step 1: Find the Antiderivative
The first step in evaluating a definite integral is to find the antiderivative (also known as the indefinite integral) of the function \(f(x) = x^2 - 1\).
The antiderivative of \(x^2\) is \(\frac{x^3}{3}\), and the antiderivative of \(-1\) is \(-x\). Therefore, the antiderivative of \(f(x)\) is:
\[
F(x) = \frac{x^3}{3} - x + C
\]
where \(C\) is the constant of integration, which we do not need for definite integrals.
### Step 2: Evaluate the Definite Integral
Now we will evaluate the definite integral from \(1\) to \(3\):
\[
\int_{1}^{3}(x^2 - 1)dx = F(3) - F(1)
\]
#### Calculate \(F(3)\):
Substituting \(x = 3\) into \(F(x)\):
\[
F(3) = \frac{3^3}{3} - 3 = \frac{27}{3} - 3 = 9 - 3 = 6
\]
#### Calculate \(F(1)\):
Substituting \(x = 1\) into \(F(x)\):
\[
F(1) = \frac{1^3}{3} - 1 = \frac{1}{3} - 1 = \frac{1}{3} - \frac{3}{3} = -\frac{2}{3}
\]
### Step 3: Compute the Final Result
Now we can find the value of the definite integral:
\[
\int_{1}^{3}(x^2 - 1)dx = F(3) - F(1) = 6 - \left(-\frac{2}{3}\right) = 6 + \frac{2}{3}
\]
To combine these, we convert \(6\) into a fraction with a denominator of \(3\):
\[
6 = \frac{18}{3}
\]
Thus,
\[
6 + \frac{2}{3} = \frac{18}{3} + \frac{2}{3} = \frac{20}{3}
\]
### Conclusion
The value of the integral \(\int_{1}^{3}(x^2 - 1)dx\) is \(\frac{20}{3}\).
### Answer Verification
Now, let's check the options provided:
- A. \(\frac{2}{3}\)
- B. \(-\frac{2}{3}\)
- C. \(-6\frac{2}{3}\)
- D. \(6\frac{2}{3}\)
None of the options match \(\frac{20}{3}\). It seems there was a misunderstanding in the options provided. The correct answer is \(\frac{20}{3}\), which is not listed.
### Summary of Key Points
- The antiderivative of \(x^2 - 1\) is \(\frac{x^3}{3} - x\).
- Evaluating the definite integral involves calculating the antiderivative at the upper and lower limits and subtracting.
- The final result of the integral \(\int_{1}^{3}(x^2 - 1)dx\) is \(\frac{20}{3}\).
- Always ensure to check the options against your calculated result to confirm correctness.
If you have any further questions or need clarification on any step, feel free to ask!