Question 208 of 480
A committee of six is to be formed by a state governor from nine state commissioners and three members of the state house of assembly. In how many ways can the members of the committee be chosen so as to include one member of the house of assembly
- A. 378 ways
- B. 462 ways
- C. 840 ways
- D. 924 ways
Correct Answer:
A
Explanation
To solve the problem of forming a committee of six members that includes one member from the state house of assembly, we can break down the process step-by-step.
### Step 1: Understand the Composition of the Committee
We need to form a committee of 6 members from:
- 9 state commissioners
- 3 members of the state house of assembly
Since the committee must include **one member from the house of assembly**, we will first select that member and then choose the remaining members from the state commissioners.
### Step 2: Choose the Member from the House of Assembly
We have 3 members in the house of assembly, and we need to choose 1. The number of ways to choose 1 member from 3 is calculated using the combination formula:
\[
\text{Number of ways to choose 1 from 3} = \binom{3}{1} = 3
\]
### Step 3: Choose the Remaining Members from State Commissioners
After selecting 1 member from the house of assembly, we need to fill the remaining 5 positions of the committee from the 9 state commissioners. The number of ways to choose 5 members from 9 is also calculated using the combination formula:
\[
\text{Number of ways to choose 5 from 9} = \binom{9}{5}
\]
Using the combination formula \(\binom{n}{r} = \frac{n!}{r!(n-r)!}\), we can calculate \(\binom{9}{5}\):
\[
\binom{9}{5} = \frac{9!}{5!(9-5)!} = \frac{9!}{5!4!}
\]
Calculating the factorials:
- \(9! = 9 \times 8 \times 7 \times 6 \times 5!\)
- \(5! = 120\)
- \(4! = 24\)
Now substituting back into the formula:
\[
\binom{9}{5} = \frac{9 \times 8 \times 7 \times 6}{4 \times 3 \times 2 \times 1} = \frac{3024}{24} = 126
\]
### Step 4: Combine the Choices
Now, we combine the number of ways to choose the member from the house of assembly and the number of ways to choose the state commissioners:
\[
\text{Total ways} = \text{Ways to choose 1 from house} \times \text{Ways to choose 5 from commissioners}
\]
\[
\text{Total ways} = 3 \times 126 = 378
\]
### Conclusion
Thus, the total number of ways to form the committee, ensuring that it includes one member from the house of assembly, is **378 ways**.
### Explanation of Other Options
- **Option B (462 ways)**: This option is incorrect because it likely results from miscalculating the combinations or not properly accounting for the requirement of including one member from the house of assembly.
- **Option C (840 ways)**: This option may arise from incorrectly assuming that all members can be chosen without the restriction of including a house member.
- **Option D (924 ways)**: This option is also incorrect, possibly due to a misunderstanding of the combination calculations or misapplying the selection criteria.
### Revision Summary
- To form a committee of 6 with 1 member from the house of assembly, first choose 1 from 3 house members.
- Then choose the remaining 5 from 9 state commissioners using combinations.
- The total number of ways to form the committee is 378.
- Always ensure to follow the problem's restrictions when calculating combinations.