Question 160 of 480
In a class of 40 students, 32 offer mathematics, 24 offer Physics, and 4 offer neither Mathematics nor Physics. How many offer both Mat
ematics and Physics?
Correct Answer:
A
Explanation
To solve the problem of how many students offer both Mathematics and Physics, we can use the principle of inclusion-exclusion. Let's break down the problem step-by-step.
### Step 1: Understand the Given Information
- Total number of students in the class: **40**
- Students offering Mathematics: **32**
- Students offering Physics: **24**
- Students offering neither Mathematics nor Physics: **4**
### Step 2: Calculate Students Offering Either Subject
First, we need to find out how many students are offering at least one of the subjects (Mathematics or Physics). Since 4 students offer neither subject, we can calculate the number of students who offer at least one subject as follows:
\[
\text{Students offering at least one subject} = \text{Total students} - \text{Students offering neither}
\]
\[
\text{Students offering at least one subject} = 40 - 4 = 36
\]
### Step 3: Use the Inclusion-Exclusion Principle
The inclusion-exclusion principle states that:
\[
\text{Number of students offering at least one subject} = \text{Number of students offering Mathematics} + \text{Number of students offering Physics} - \text{Number of students offering both subjects}
\]
Let \( x \) be the number of students offering both Mathematics and Physics. We can set up the equation:
\[
36 = 32 + 24 - x
\]
### Step 4: Solve for \( x \)
Now, we can simplify the equation:
\[
36 = 56 - x
\]
Rearranging gives us:
\[
x = 56 - 36
\]
\[
x = 20
\]
### Conclusion
Thus, the number of students who offer both Mathematics and Physics is **20**.
### Explanation of Other Options
- **Option A (20)**: This is the correct answer as derived from our calculations.
- **Option B (16)**: This option is incorrect because it does not account for the total number of students correctly when applying the inclusion-exclusion principle.
- **Option C (8)**: This option is also incorrect as it underestimates the overlap between the two subjects.
- **Option D (4)**: This option is incorrect as it suggests a very small overlap, which does not align with the total number of students offering either subject.
### Revision Summary
- Use the inclusion-exclusion principle to find the number of students in overlapping sets.
- Calculate the total number of students offering at least one subject by subtracting those offering neither.
- Set up the equation based on the principle and solve for the unknown.
- Always double-check your calculations to ensure accuracy.
This thorough approach ensures that you understand not just the answer, but the reasoning behind it, which is crucial for success in mathematics exams.