Question 159 of 480
Simplify 213\(_4\) x 23\(_4\)
- A. 103114
- B. 103214
- C. 122314
- D. 132114
Correct Answer:
C
Explanation
To simplify the multiplication of \(213_4\) and \(23_4\), we will first convert both numbers from base 4 to base 10, perform the multiplication in base 10, and then convert the result back to base 4.
### Step 1: Convert \(213_4\) to Base 10
The number \(213_4\) can be converted to base 10 using the formula:
\[
n = d_k \cdot b^k + d_{k-1} \cdot b^{k-1} + \ldots + d_1 \cdot b^1 + d_0 \cdot b^0
\]
where \(d\) are the digits of the number, \(b\) is the base (which is 4 in this case), and \(k\) is the position of the digit from the right (starting from 0).
For \(213_4\):
- The digit \(2\) is in the \(4^2\) place.
- The digit \(1\) is in the \(4^1\) place.
- The digit \(3\) is in the \(4^0\) place.
Calculating each term:
\[
2 \cdot 4^2 = 2 \cdot 16 = 32
\]
\[
1 \cdot 4^1 = 1 \cdot 4 = 4
\]
\[
3 \cdot 4^0 = 3 \cdot 1 = 3
\]
Now, add these values together:
\[
32 + 4 + 3 = 39
\]
So, \(213_4 = 39_{10}\).
### Step 2: Convert \(23_4\) to Base 10
Now, we convert \(23_4\) to base 10 using the same method:
For \(23_4\):
- The digit \(2\) is in the \(4^1\) place.
- The digit \(3\) is in the \(4^0\) place.
Calculating each term:
\[
2 \cdot 4^1 = 2 \cdot 4 = 8
\]
\[
3 \cdot 4^0 = 3 \cdot 1 = 3
\]
Now, add these values together:
\[
8 + 3 = 11
\]
So, \(23_4 = 11_{10}\).
### Step 3: Multiply the Base 10 Values
Now we multiply the two base 10 values we obtained:
\[
39 \times 11 = 429
\]
### Step 4: Convert \(429_{10}\) Back to Base 4
To convert \(429_{10}\) back to base 4, we repeatedly divide by 4 and keep track of the remainders:
1. \(429 \div 4 = 107\) remainder \(1\)
2. \(107 \div 4 = 26\) remainder \(3\)
3. \(26 \div 4 = 6\) remainder \(2\)
4. \(6 \div 4 = 1\) remainder \(2\)
5. \(1 \div 4 = 0\) remainder \(1\)
Now, we read the remainders from bottom to top to get the base 4 representation:
Thus, \(429_{10} = 12321_4\).
### Step 5: Check the Options
Now, let's compare our result \(12321_4\) with the provided options:
A. \(103114\)
B. \(103214\)
C. \(122314\)
D. \(132114\)
None of the options match \(12321_4\). It seems there was a misunderstanding in the options provided.
### Conclusion
The correct answer for the multiplication of \(213_4\) and \(23_4\) is \(12321_4\), which is not listed among the options.
### Revision Summary
- Convert numbers from base 4 to base 10 using positional values.
- Multiply the base 10 results.
- Convert the product back to base 4 using repeated division and remainders.
- Always verify your final answer against the provided options.
If you encounter discrepancies, double-check your calculations and ensure the options are correct.