Question 167 of 480
The sum of four numbers is 1214\(_5\). What is the average expressed in base five?
- A. 114
- B. 141
- C. 401
- D. 411
Correct Answer:
B
Explanation
To solve the problem of finding the average of four numbers given their sum in base five, we will follow a systematic approach. Let's break it down step-by-step.
### Step 1: Understanding the Sum in Base Five
The sum of the four numbers is given as \(1214_5\). This means that the number is in base five, and we need to convert it to base ten (decimal) to perform our calculations.
**Conversion from Base Five to Base Ten:**
The base five number \(1214_5\) can be converted to decimal using the formula:
\[
n = d_k \cdot b^k + d_{k-1} \cdot b^{k-1} + \ldots + d_1 \cdot b^1 + d_0 \cdot b^0
\]
Where \(d\) are the digits, \(b\) is the base (which is 5 in this case), and \(k\) is the position of the digit from the right (starting from 0).
For \(1214_5\):
- The digit \(1\) is in the \(3^{rd}\) position (from the right), so it contributes \(1 \cdot 5^3\).
- The digit \(2\) is in the \(2^{nd}\) position, contributing \(2 \cdot 5^2\).
- The digit \(1\) is in the \(1^{st}\) position, contributing \(1 \cdot 5^1\).
- The digit \(4\) is in the \(0^{th}\) position, contributing \(4 \cdot 5^0\).
Calculating each term:
- \(1 \cdot 5^3 = 1 \cdot 125 = 125\)
- \(2 \cdot 5^2 = 2 \cdot 25 = 50\)
- \(1 \cdot 5^1 = 1 \cdot 5 = 5\)
- \(4 \cdot 5^0 = 4 \cdot 1 = 4\)
Now, we sum these contributions:
\[
125 + 50 + 5 + 4 = 184
\]
So, \(1214_5\) in decimal is \(184\).
### Step 2: Finding the Average
To find the average of the four numbers, we divide the total sum by the number of numbers (which is 4):
\[
\text{Average} = \frac{\text{Sum}}{\text{Number of Values}} = \frac{184}{4} = 46
\]
### Step 3: Converting the Average Back to Base Five
Now, we need to convert the average \(46\) from decimal back to base five.
**Conversion from Decimal to Base Five:**
To convert a decimal number to base five, we repeatedly divide the number by 5 and keep track of the remainders.
1. \(46 \div 5 = 9\) with a remainder of \(1\).
2. \(9 \div 5 = 1\) with a remainder of \(4\).
3. \(1 \div 5 = 0\) with a remainder of \(1\).
Now, we read the remainders from bottom to top, which gives us \(141_5\).
### Conclusion: The Correct Option
The average expressed in base five is \(141_5\), which corresponds to option **B**.
### Explanation of Other Options
- **Option A (114)**: This would represent a smaller average than calculated. In decimal, \(114_5\) converts to \(29\) in decimal, which is not correct.
- **Option C (401)**: This represents a larger average. In decimal, \(401_5\) converts to \(101\), which is also incorrect.
- **Option D (411)**: This is another incorrect option. In decimal, \(411_5\) converts to \(102\), which does not match our calculated average.
### Revision Summary
- Convert the base five number to decimal to find the sum.
- Calculate the average by dividing the sum by the number of values.
- Convert the average back to base five for the final answer.
- The correct average in base five is \(141_5\) (Option B).