Question 811 of 949
A car accelerates uniformly from rest and reaches a speed of 20 m/s in 5 seconds. What is the car's rectilinear acceleration?
- 2 m/s²
- 4 m/s²
- 5 m/s²
- 10 m/s²
Correct Answer:
B
Explanation
To determine the car's rectilinear acceleration, we can use the basic kinematic equation that relates acceleration, initial velocity, final velocity, and time. The equation we will use is:
\[
a = \frac{v_f - v_i}{t}
\]
Where:
- \( a \) is the acceleration,
- \( v_f \) is the final velocity,
- \( v_i \) is the initial velocity,
- \( t \) is the time taken.
### Step-by-Step Explanation
1. **Identify the Given Values**:
- The car starts from rest, so the initial velocity \( v_i = 0 \, \text{m/s} \).
- The final velocity \( v_f = 20 \, \text{m/s} \).
- The time taken to reach this speed \( t = 5 \, \text{s} \).
2. **Substitute the Values into the Formula**:
We can now substitute the known values into the acceleration formula:
\[
a = \frac{20 \, \text{m/s} - 0 \, \text{m/s}}{5 \, \text{s}}
\]
3. **Calculate the Acceleration**:
\[
a = \frac{20 \, \text{m/s}}{5 \, \text{s}} = 4 \, \text{m/s}^2
\]
Thus, the car's rectilinear acceleration is **4 m/s²**.
### Why Option B is Correct
- The calculation shows that the acceleration is \( 4 \, \text{m/s}^2 \), which corresponds to option B. This means that for every second, the car's speed increases by 4 meters per second.
### Explanation of Other Options
- **Option A: 2 m/s²**: This option is incorrect because if the acceleration were 2 m/s², the car would only reach a speed of \( 2 \, \text{m/s} \times 5 \, \text{s} = 10 \, \text{m/s} \) after 5 seconds, which is not the final speed given in the problem.
- **Option C: 5 m/s²**: This option is also incorrect. If the acceleration were 5 m/s², the car would reach a speed of \( 5 \, \text{m/s} \times 5 \, \text{s} = 25 \, \text{m/s} \) after 5 seconds, which exceeds the final speed of 20 m/s.
- **Option D: 10 m/s²**: This option is incorrect as well. An acceleration of 10 m/s² would result in a final speed of \( 10 \, \text{m/s} \times 5 \, \text{s} = 50 \, \text{m/s} \), which is far greater than the specified final speed of 20 m/s.
### Common Pitfalls
- **Misunderstanding Initial Conditions**: Always ensure you correctly identify the initial velocity, especially if the object starts from rest.
- **Forgetting to Use the Correct Formula**: Make sure to use the appropriate kinematic equations for uniformly accelerated motion.
- **Units**: Be careful with units; ensure that time is in seconds and speed is in meters per second to maintain consistency.
### Revision Summary
- The formula for acceleration is \( a = \frac{v_f - v_i}{t} \).
- For this problem, \( v_i = 0 \, \text{m/s} \), \( v_f = 20 \, \text{m/s} \), and \( t = 5 \, \text{s} \).
- The calculated acceleration is \( 4 \, \text{m/s}^2 \), which corresponds to option B.
- Always check your calculations and ensure you understand the physical meaning of the variables involved.