Explanation
To determine the car's rectilinear acceleration, we can use the basic kinematic equation that relates acceleration, initial velocity, final velocity, and time. Let's break this down step-by-step.
### Step 1: Identify the Given Information
- **Initial velocity (u)**: The car starts from rest, so \( u = 0 \, \text{m/s} \).
- **Final velocity (v)**: The car accelerates to a speed of \( v = 30 \, \text{m/s} \).
- **Time (t)**: The time taken to reach this speed is \( t = 10 \, \text{s} \).
### Step 2: Use the Formula for Acceleration
The formula for acceleration (\( a \)) when you know the initial velocity, final velocity, and time is given by:
\[
a = \frac{v - u}{t}
\]
### Step 3: Substitute the Values into the Formula
Now, we can substitute the values we have into the formula:
\[
a = \frac{30 \, \text{m/s} - 0 \, \text{m/s}}{10 \, \text{s}}
\]
### Step 4: Perform the Calculation
Calculating the numerator:
\[
30 \, \text{m/s} - 0 \, \text{m/s} = 30 \, \text{m/s}
\]
Now, divide by the time:
\[
a = \frac{30 \, \text{m/s}}{10 \, \text{s}} = 3 \, \text{m/s}^2
\]
### Conclusion
Thus, the car's rectilinear acceleration is \( 3 \, \text{m/s}^2 \). Therefore, the correct option is **B**.
### Explanation of Other Options
- **Option A (2 m/s²)**: This value is too low. If the acceleration were 2 m/s², the car would not reach 30 m/s in 10 seconds. Using the same formula, \( a = 2 \, \text{m/s}^2 \) would yield a final speed of only \( 20 \, \text{m/s} \) after 10 seconds.
- **Option C (5 m/s²)**: This value is too high. If the acceleration were 5 m/s², the car would reach a final speed of \( 50 \, \text{m/s} \) in 10 seconds, which exceeds the given final speed of 30 m/s.
- **Option D (6 m/s²)**: This value is also too high. An acceleration of 6 m/s² would result in a final speed of \( 60 \, \text{m/s} \) after 10 seconds, which again is not consistent with the problem statement.
### Common Pitfalls
- **Misunderstanding the initial conditions**: Remember that the car starts from rest, which means the initial velocity is zero.
- **Forgetting to convert units**: Ensure that all units are consistent (e.g., time in seconds, speed in meters per second).
- **Confusing acceleration with speed**: Acceleration is the change in speed over time, not the final speed itself.
### Revision Summary
- The formula for acceleration is \( a = \frac{v - u}{t} \).
- For this problem, \( u = 0 \, \text{m/s} \), \( v = 30 \, \text{m/s} \), and \( t = 10 \, \text{s} \).
- The calculated acceleration is \( 3 \, \text{m/s}^2 \), making option B the correct answer.
- Always check the reasonableness of your answer by considering the context of the problem.