Question 206 of 949
On a fairly cool rainy day when the temperature is 20oC, the length of a steel railroad track is 20m. What will be its length on a hot a dry day when the temperature is 40oC?
[coefficient of linear expansion of steel = 11 x 10-6K-1]
- A. 20.013m
- B. 20.009m
- C. 20.004m
- D. 20.002m
Correct Answer:
C
Explanation
To determine the length of a steel railroad track on a hot day when the temperature increases, we can use the formula for linear expansion. The formula for linear expansion is given by:
\[
\Delta L = L_0 \cdot \alpha \cdot \Delta T
\]
Where:
- \(\Delta L\) = change in length
- \(L_0\) = original length of the object
- \(\alpha\) = coefficient of linear expansion
- \(\Delta T\) = change in temperature
### Step-by-Step Calculation
1. **Identify the given values:**
- Original length of the track, \(L_0 = 20 \, \text{m}\)
- Coefficient of linear expansion for steel, \(\alpha = 11 \times 10^{-6} \, \text{K}^{-1}\)
- Initial temperature, \(T_1 = 20^\circ C\)
- Final temperature, \(T_2 = 40^\circ C\)
2. **Calculate the change in temperature (\(\Delta T\)):**
\[
\Delta T = T_2 - T_1 = 40^\circ C - 20^\circ C = 20 \, \text{K}
\]
3. **Calculate the change in length (\(\Delta L\)):**
\[
\Delta L = L_0 \cdot \alpha \cdot \Delta T
\]
Substituting the values:
\[
\Delta L = 20 \, \text{m} \cdot (11 \times 10^{-6} \, \text{K}^{-1}) \cdot 20 \, \text{K}
\]
\[
\Delta L = 20 \cdot 11 \cdot 20 \times 10^{-6} \, \text{m}
\]
\[
\Delta L = 4400 \times 10^{-6} \, \text{m} = 0.0044 \, \text{m}
\]
4. **Calculate the new length of the track (\(L\)):**
\[
L = L_0 + \Delta L
\]
\[
L = 20 \, \text{m} + 0.0044 \, \text{m} = 20.0044 \, \text{m}
\]
5. **Round the answer to three decimal places:**
\[
L \approx 20.004 \, \text{m}
\]
### Conclusion
The length of the steel railroad track on a hot dry day when the temperature is 40°C will be approximately **20.004 m**. Therefore, the correct option is **C. 20.004m**.
### Explanation of Other Options
- **Option A (20.013m)**: This value is too high. It likely results from an incorrect calculation of the change in length or an incorrect assumption about the temperature change.
- **Option B (20.009m)**: This value is also too high and does not accurately reflect the calculated change in length based on the given temperature increase.
- **Option D (20.002m)**: This value is too low and does not account for the full change in length due to the temperature increase.
### Revision Summary
- Use the linear expansion formula: \(\Delta L = L_0 \cdot \alpha \cdot \Delta T\).
- Calculate the change in temperature accurately.
- Substitute values carefully to find the change in length.
- Add the change in length to the original length to find the new length.