Question 199 of 949
A 90cm uniform lever has a load of 30N suspended at 15cm from one of its ends. If the fulcrum is at the center of gravity, the force that must be applied at its other end to keep it in horizontal equilibrium is
- A. 15N
- B. 20N
- C. 30N
- D. 60N
Correct Answer:
B
Explanation
To solve the problem of finding the force that must be applied at one end of a lever to keep it in horizontal equilibrium, we can use the principles of moments (torque). Let's break down the problem step-by-step.
### Step 1: Understand the Setup
- We have a uniform lever that is 90 cm long.
- A load of 30 N is suspended 15 cm from one end of the lever.
- The fulcrum (pivot point) is located at the center of the lever, which is at 45 cm from either end.
### Step 2: Identify Distances
- The distance from the fulcrum to the load (30 N) is:
\[
\text{Distance from fulcrum to load} = 45 \text{ cm} - 15 \text{ cm} = 30 \text{ cm}
\]
- The distance from the fulcrum to the point where we will apply the force (let's call this force \( F \)) is:
\[
\text{Distance from fulcrum to applied force} = 90 \text{ cm} - 45 \text{ cm} = 45 \text{ cm}
\]
### Step 3: Apply the Principle of Moments
For the lever to be in horizontal equilibrium, the clockwise moments must equal the counterclockwise moments about the fulcrum.
- **Clockwise Moment due to the Load**:
\[
\text{Moment} = \text{Force} \times \text{Distance} = 30 \text{ N} \times 30 \text{ cm} = 900 \text{ N cm}
\]
- **Counterclockwise Moment due to the Applied Force**:
\[
\text{Moment} = F \times 45 \text{ cm}
\]
### Step 4: Set Up the Equation
To maintain equilibrium:
\[
\text{Clockwise Moment} = \text{Counterclockwise Moment}
\]
This gives us the equation:
\[
30 \text{ N} \times 30 \text{ cm} = F \times 45 \text{ cm}
\]
Substituting the moments:
\[
900 \text{ N cm} = F \times 45 \text{ cm}
\]
### Step 5: Solve for \( F \)
To find \( F \), we rearrange the equation:
\[
F = \frac{900 \text{ N cm}}{45 \text{ cm}} = 20 \text{ N}
\]
### Conclusion
The force that must be applied at the other end of the lever to keep it in horizontal equilibrium is **20 N**. Therefore, the correct option is **B**.
### Explanation of Other Options
- **Option A (15 N)**: This is incorrect because it does not provide enough counterclockwise moment to balance the 900 N cm of clockwise moment created by the load.
- **Option C (30 N)**: This would create a counterclockwise moment of \( 30 \text{ N} \times 45 \text{ cm} = 1350 \text{ N cm} \), which is too large compared to the 900 N cm from the load.
- **Option D (60 N)**: This would create an even larger counterclockwise moment of \( 60 \text{ N} \times 45 \text{ cm} = 2700 \text{ N cm} \), which is also excessive.
### Revision Summary
- The lever is in equilibrium when clockwise moments equal counterclockwise moments.
- Calculate moments using the formula: Moment = Force × Distance from the fulcrum.
- Ensure to correctly identify distances from the fulcrum for both the load and the applied force.
- The correct force to maintain equilibrium in this scenario is 20 N.