Question 194 of 949
A hose of cross-sectional area 0.5m2 is used to discharge water from a water tanker at a velocity of 60ms-1 in 20s into a container. If the container is filled completely, the volume of the container is
- A. 240m3
- B. 600m 3
- C. 2400m 3
- D. 6000m3
Correct Answer:
B
Explanation
To determine the volume of water discharged from the hose into the container, we can use the relationship between flow rate, cross-sectional area, and velocity. Let's break down the problem step-by-step.
### Step 1: Understand the Flow Rate
The flow rate (Q) of a fluid can be calculated using the formula:
\[
Q = A \times v
\]
where:
- \( Q \) is the flow rate in cubic meters per second (m³/s),
- \( A \) is the cross-sectional area of the hose in square meters (m²),
- \( v \) is the velocity of the fluid in meters per second (m/s).
### Step 2: Plug in the Values
From the problem, we know:
- The cross-sectional area \( A = 0.5 \, \text{m}^2 \)
- The velocity \( v = 60 \, \text{m/s} \)
Now, we can calculate the flow rate:
\[
Q = 0.5 \, \text{m}^2 \times 60 \, \text{m/s} = 30 \, \text{m}^3/\text{s}
\]
### Step 3: Calculate the Total Volume Discharged
Next, we need to find out how much water is discharged in 20 seconds. The total volume \( V \) can be calculated using the formula:
\[
V = Q \times t
\]
where:
- \( V \) is the total volume in cubic meters (m³),
- \( t \) is the time in seconds (s).
Substituting the values we have:
\[
V = 30 \, \text{m}^3/\text{s} \times 20 \, \text{s} = 600 \, \text{m}^3
\]
### Conclusion
Thus, the volume of the container that is filled completely is **600 m³**.
### Explanation of the Options
- **Option A: 240 m³** - This is incorrect because it underestimates the volume based on the flow rate and time calculated.
- **Option B: 600 m³** - This is the correct answer as derived from the calculations above.
- **Option C: 2400 m³** - This is incorrect; it suggests a much larger volume than what is calculated based on the given flow rate and time.
- **Option D: 6000 m³** - This is also incorrect; it is significantly larger than the calculated volume and does not align with the flow rate and time.
### Common Pitfalls
1. **Misunderstanding Units**: Ensure that all units are consistent (e.g., area in m², velocity in m/s).
2. **Forgetting to Multiply by Time**: It’s crucial to multiply the flow rate by the time to find the total volume.
3. **Incorrectly Calculating Flow Rate**: Double-check the multiplication of area and velocity to avoid errors in flow rate.
### Revision Summary
- The flow rate is calculated using the formula \( Q = A \times v \).
- The total volume discharged is found by multiplying the flow rate by the time: \( V = Q \times t \).
- For this problem, the correct volume of the container is **600 m³**.
- Always ensure units are consistent and remember to multiply by time to find total volume.