Question 175 of 949
An electric iron is rated 1000W, 230V. What is the resistance of its elements?
- A. 51.9Ω
- B. 52.9Ω
- C. 55.9Ω
- D. 57.6Ω
Correct Answer:
B
Explanation
To find the resistance of the electric iron rated at 1000W and 230V, we can use Ohm's Law and the power formula. Let's break this down step-by-step.
### Step 1: Understand the relationship between power, voltage, and resistance
The power (P) consumed by an electrical device can be expressed in terms of voltage (V) and resistance (R) using the formula:
\[
P = \frac{V^2}{R}
\]
Where:
- \( P \) is the power in watts (W)
- \( V \) is the voltage in volts (V)
- \( R \) is the resistance in ohms (Ω)
### Step 2: Rearranging the formula to find resistance
We need to find the resistance \( R \). Rearranging the formula gives us:
\[
R = \frac{V^2}{P}
\]
### Step 3: Plugging in the values
Now, we can substitute the given values into the formula. The electric iron has a power rating of 1000W and operates at a voltage of 230V.
\[
R = \frac{(230V)^2}{1000W}
\]
Calculating \( (230V)^2 \):
\[
(230)^2 = 52900
\]
Now substituting this back into the equation for resistance:
\[
R = \frac{52900}{1000} = 52.9Ω
\]
### Conclusion: The correct answer
Thus, the resistance of the electric iron is **52.9Ω**, which corresponds to option **B**.
### Step 4: Explanation of other options
Now, let's analyze the other options to understand why they are incorrect:
- **Option A: 51.9Ω**
- This value is lower than the calculated resistance. It may arise from a miscalculation or misunderstanding of the power formula.
- **Option C: 55.9Ω**
- This value is higher than the calculated resistance. It could be a result of incorrectly applying the formula or miscalculating the square of the voltage.
- **Option D: 57.6Ω**
- This value is significantly higher than the calculated resistance. Similar to option C, it likely results from a miscalculation.
### Common Pitfalls
1. **Misapplying the formula**: Ensure you are using the correct formula for power and rearranging it properly.
2. **Calculating the square of the voltage**: Double-check your arithmetic when squaring the voltage.
3. **Units**: Always keep track of your units (watts, volts, ohms) to avoid confusion.
### Revision Summary
- Use the formula \( P = \frac{V^2}{R} \) to relate power, voltage, and resistance.
- Rearrange to find resistance: \( R = \frac{V^2}{P} \).
- Substitute the given values carefully to avoid calculation errors.
- The resistance of the electric iron is **52.9Ω** (Option B).