Question 182 of 949
The percentage of the original nuclei of the sample of a radioactive substance left after 5 half - lives is
Correct Answer:
C
Explanation
To determine the percentage of the original nuclei of a radioactive substance left after 5 half-lives, we first need to understand the concept of half-life and how it affects the quantity of a radioactive substance over time.
### Step-by-Step Explanation
1. **Understanding Half-Life**:
- The half-life of a radioactive substance is the time required for half of the radioactive nuclei in a sample to decay. For example, if you start with 100 nuclei, after one half-life, you will have 50 nuclei remaining.
2. **Calculating Remaining Nuclei**:
- After each half-life, the amount of the substance reduces to half of what it was at the beginning of that period. This can be expressed mathematically:
- After 1 half-life: \( N = \frac{N_0}{2} \)
- After 2 half-lives: \( N = \frac{N_0}{2^2} = \frac{N_0}{4} \)
- After 3 half-lives: \( N = \frac{N_0}{2^3} = \frac{N_0}{8} \)
- After 4 half-lives: \( N = \frac{N_0}{2^4} = \frac{N_0}{16} \)
- After 5 half-lives: \( N = \frac{N_0}{2^5} = \frac{N_0}{32} \)
3. **Finding the Percentage Remaining**:
- To find the percentage of the original nuclei remaining after 5 half-lives, we can use the formula:
\[
\text{Percentage remaining} = \left( \frac{N}{N_0} \right) \times 100\%
\]
- Substituting \( N = \frac{N_0}{32} \):
\[
\text{Percentage remaining} = \left( \frac{N_0/32}{N_0} \right) \times 100\% = \left( \frac{1}{32} \right) \times 100\% \approx 3.125\%
\]
4. **Rounding**:
- When rounding 3.125% to the nearest whole number, we get approximately 3%. Therefore, the correct answer is **C. 3%**.
### Why Other Options Are Incorrect
- **Option A: 8%**:
- This would imply that after 5 half-lives, more than 3% of the original nuclei remain. However, as shown in the calculations, only about 3.125% remains, which is significantly less than 8%.
- **Option B: 5%**:
- Similar to option A, this option suggests that a larger percentage of the original nuclei remains than what is actually calculated. The decay process is exponential, and after 5 half-lives, the remaining percentage is much lower than 5%.
- **Option D: 1%**:
- This option underestimates the remaining nuclei. While it is true that the amount decreases significantly, the calculation shows that approximately 3.125% remains, which is higher than 1%.
### Common Pitfalls
- **Misunderstanding Half-Life**: Students often confuse the concept of half-life with a linear decay process. Remember, the decay is exponential, meaning the amount decreases rapidly at first and then slows down.
- **Rounding Errors**: Be careful when rounding percentages. Always calculate the exact percentage before rounding to ensure accuracy.
### Revision Summary
- The percentage of original nuclei remaining after 5 half-lives is approximately 3.125%.
- The formula for remaining nuclei after \( n \) half-lives is \( N = \frac{N_0}{2^n} \).
- After 5 half-lives, the remaining percentage is calculated as \( \left( \frac{1}{32} \right) \times 100\% \).
- Common mistakes include misunderstanding the exponential nature of decay and incorrect rounding of percentages.