Question 96 of 480
Factorize 4x2 - 9y2 + 20x + 25
- A. (2x -3y + 5)(2x - 3y - 5)
- B. (2x - 3y)(2x + 3y)
- C. (2x - 3y +5)(2x + 3y + 5)
- D. (2x + 5)(2x - 9y +5)
Correct Answer:
C
Explanation
To factor the expression \(4x^2 - 9y^2 + 20x + 25\), we will follow a systematic approach.
### Step 1: Rearranging the Expression
First, let's rearrange the expression to group the quadratic terms and the constant terms:
\[
4x^2 + 20x - 9y^2 + 25
\]
### Step 2: Completing the Square
Next, we will complete the square for the \(x\) terms. The expression \(4x^2 + 20x\) can be factored as follows:
1. Factor out the coefficient of \(x^2\) (which is 4):
\[
4(x^2 + 5x)
\]
2. To complete the square for \(x^2 + 5x\), we take half of the coefficient of \(x\) (which is 5), square it, and add and subtract it inside the parentheses:
\[
\text{Half of 5 is } \frac{5}{2}, \text{ and squaring it gives } \left(\frac{5}{2}\right)^2 = \frac{25}{4}.
\]
Thus, we rewrite:
\[
4\left(x^2 + 5x + \frac{25}{4} - \frac{25}{4}\right) = 4\left((x + \frac{5}{2})^2 - \frac{25}{4}\right)
\]
3. Distributing the 4 gives:
\[
4\left(x + \frac{5}{2}\right)^2 - 25
\]
### Step 3: Substitute Back into the Expression
Now, substituting back into the expression, we have:
\[
4\left(x + \frac{5}{2}\right)^2 - 25 - 9y^2 + 25
\]
The \(+25\) and \(-25\) cancel out, leaving us with:
\[
4\left(x + \frac{5}{2}\right)^2 - 9y^2
\]
### Step 4: Recognizing the Difference of Squares
The expression \(4\left(x + \frac{5}{2}\right)^2 - 9y^2\) is a difference of squares, which can be factored using the formula \(a^2 - b^2 = (a - b)(a + b)\).
Here, let:
- \(a = 2\left(x + \frac{5}{2}\right)\)
- \(b = 3y\)
Thus, we can write:
\[
(2\left(x + \frac{5}{2}\right) - 3y)(2\left(x + \frac{5}{2}\right) + 3y)
\]
### Step 5: Simplifying the Factors
Now, simplifying the factors:
1. The first factor becomes:
\[
2x + 5 - 3y
\]
2. The second factor becomes:
\[
2x + 5 + 3y
\]
So, we can write the factored form as:
\[
(2x - 3y + 5)(2x + 3y + 5)
\]
### Conclusion: Correct Option
The correct option is **C**: \((2x - 3y + 5)(2x + 3y + 5)\).
### Explanation of Other Options
- **Option A**: \((2x - 3y + 5)(2x - 3y - 5)\) is incorrect because it does not represent the correct factors derived from the expression.
- **Option B**: \((2x - 3y)(2x + 3y)\) is incorrect as it does not account for the constant term \(+5\) in the original expression.
- **Option D**: \((2x + 5)(2x - 9y + 5)\) is incorrect because it does not match the structure of the factored form we derived.
### Revision Summary
- Factor the quadratic expression by completing the square.
- Recognize the difference of squares to factor further.
- Ensure to simplify and check each factor against the original expression.
- Understand why other options do not satisfy the original equation.