Question 59 of 480
if (x - 1), (x + 1) and (x - 2) are factors of the polynomial ax\(^3\) + bx\(^2\) + cx - 1, find a, b, c in that order.
- A. -1/2, 1., 1/2
- B. 1/2, 1, 1/2
- C. 1/2, 1, -1/2
- D. 1/2, -1, 1/2
Correct Answer:
A
Explanation
To solve the problem, we need to find the coefficients \( a \), \( b \), and \( c \) in the polynomial \( ax^3 + bx^2 + cx - 1 \) given that \( (x - 1) \), \( (x + 1) \), and \( (x - 2) \) are factors of this polynomial.
### Step-by-Step Explanation
1. **Understanding Factors**:
If \( (x - 1) \), \( (x + 1) \), and \( (x - 2) \) are factors of the polynomial, then the polynomial must equal zero when \( x = 1 \), \( x = -1 \), and \( x = 2 \). This means we can substitute these values into the polynomial to create a system of equations.
2. **Setting Up the Equations**:
- For \( x = 1 \):
\[
a(1)^3 + b(1)^2 + c(1) - 1 = 0 \implies a + b + c - 1 = 0 \implies a + b + c = 1 \quad \text{(Equation 1)}
\]
- For \( x = -1 \):
\[
a(-1)^3 + b(-1)^2 + c(-1) - 1 = 0 \implies -a + b - c - 1 = 0 \implies -a + b - c = 1 \quad \text{(Equation 2)}
\]
- For \( x = 2 \):
\[
a(2)^3 + b(2)^2 + c(2) - 1 = 0 \implies 8a + 4b + 2c - 1 = 0 \implies 8a + 4b + 2c = 1 \quad \text{(Equation 3)}
\]
3. **Solving the System of Equations**:
We now have a system of three equations:
- \( a + b + c = 1 \) (Equation 1)
- \( -a + b - c = 1 \) (Equation 2)
- \( 8a + 4b + 2c = 1 \) (Equation 3)
Let's solve these equations step by step.
**From Equation 1**:
\[
c = 1 - a - b \quad \text{(Substituting into other equations)}
\]
**Substituting into Equation 2**:
\[
-a + b - (1 - a - b) = 1 \implies -a + b - 1 + a + b = 1 \implies 2b - 1 = 1 \implies 2b = 2 \implies b = 1
\]
**Substituting \( b = 1 \) back into Equation 1**:
\[
a + 1 + c = 1 \implies a + c = 0 \implies c = -a
\]
**Substituting \( b = 1 \) and \( c = -a \) into Equation 3**:
\[
8a + 4(1) + 2(-a) = 1 \implies 8a + 4 - 2a = 1 \implies 6a + 4 = 1 \implies 6a = -3 \implies a = -\frac{1}{2}
\]
**Finding \( c \)**:
\[
c = -a = -\left(-\frac{1}{2}\right) = \frac{1}{2}
\]
4. **Final Values**:
We have found:
- \( a = -\frac{1}{2} \)
- \( b = 1 \)
- \( c = \frac{1}{2} \)
### Conclusion
Thus, the values of \( a \), \( b \), and \( c \) are:
- \( a = -\frac{1}{2} \)
- \( b = 1 \)
- \( c = \frac{1}{2} \)
The correct option is **A: -1/2, 1, 1/2**.
### Why Other Options Are Incorrect:
- **Option B (1/2, 1, 1/2)**: This suggests \( a = 1/2 \), which contradicts our finding that \( a = -1/2 \).
- **Option C (1/2, 1, -1/2)**: This incorrectly states \( c = -1/2 \) instead of \( c = 1/2 \).
- **Option D (1/2, -1, 1/2)**: This incorrectly states \( b = -1 \) instead of \( b = 1 \).
### Revision Summary:
- Factors of a polynomial lead to equations when substituted with their roots.
- Solve the system of equations to find the coefficients.
- Always check each option against the derived values to confirm correctness.
- Be careful with signs and substitutions to avoid common pitfalls.