Question 61 of 480
Solve the inequality 2 - x > x\(^2\).
- A. x < -2 or x > 1
- B. x > 2 or x< -1
- C. -1 < x < 2
- D. -2 < x < 1
Correct Answer:
D
Explanation
To solve the inequality \(2 - x > x^2\), we will follow a systematic approach. Let's break it down step-by-step.
### Step 1: Rearranging the Inequality
First, we want to rearrange the inequality so that all terms are on one side. We can do this by moving \(x^2\) and \(x\) to the left side:
\[
2 - x - x^2 > 0
\]
This can be rewritten as:
\[
-x^2 - x + 2 > 0
\]
### Step 2: Reorganizing the Terms
To make it easier to factor, we can multiply the entire inequality by -1 (remember that this reverses the inequality sign):
\[
x^2 + x - 2 < 0
\]
### Step 3: Factoring the Quadratic
Next, we need to factor the quadratic expression \(x^2 + x - 2\). We are looking for two numbers that multiply to -2 (the constant term) and add to 1 (the coefficient of \(x\)). The numbers that satisfy this are 2 and -1. Thus, we can factor the quadratic as follows:
\[
(x + 2)(x - 1) < 0
\]
### Step 4: Finding the Critical Points
The critical points occur when the expression equals zero:
\[
(x + 2) = 0 \quad \Rightarrow \quad x = -2
\]
\[
(x - 1) = 0 \quad \Rightarrow \quad x = 1
\]
These critical points divide the number line into intervals. We will test each interval to determine where the inequality holds true.
### Step 5: Testing the Intervals
The critical points divide the number line into three intervals:
1. \( (-\infty, -2) \)
2. \( (-2, 1) \)
3. \( (1, \infty) \)
We will test a point from each interval in the inequality \( (x + 2)(x - 1) < 0 \).
- **Interval 1: \( (-\infty, -2) \)**
Choose \(x = -3\):
\[
(-3 + 2)(-3 - 1) = (-1)(-4) = 4 \quad (\text{not less than } 0)
\]
- **Interval 2: \( (-2, 1) \)**
Choose \(x = 0\):
\[
(0 + 2)(0 - 1) = (2)(-1) = -2 \quad (\text{less than } 0)
\]
- **Interval 3: \( (1, \infty) \)**
Choose \(x = 2\):
\[
(2 + 2)(2 - 1) = (4)(1) = 4 \quad (\text{not less than } 0)
\]
### Step 6: Conclusion
The inequality \( (x + 2)(x - 1) < 0 \) holds true in the interval \( (-2, 1) \). Therefore, the solution to the inequality \( 2 - x > x^2 \) is:
\[
-2 < x < 1
\]
### Final Answer
The correct option is **D. -2 < x < 1**.
### Explanation of Other Options
- **Option A: \(x < -2\) or \(x > 1\)**
This option suggests that the inequality holds outside the interval we found, which is incorrect based on our testing.
- **Option B: \(x > 2\) or \(x < -1\)**
This option incorrectly includes values greater than 2, which do not satisfy the inequality.
- **Option C: \(-1 < x < 2\)**
This option incorrectly includes values greater than 1, which do not satisfy the inequality.
### Revision Summary
- Rearranged the inequality to \(x^2 + x - 2 < 0\).
- Factored the quadratic to \((x + 2)(x - 1) < 0\).
- Tested intervals to find where the inequality holds.
- Concluded that the solution is \(-2 < x < 1\).