Question 127 of 480
Evaluate \(\int \sin 3x \mathrm d x\)
- A. (2/3) cos 3x + c
- B. (1/3) cos 3x + c
- C. (-1/3) cos 3x + c
- D. (-2/3) cos 3x + c
Correct Answer:
C
Explanation
To evaluate the integral \(\int \sin 3x \, \mathrm{d}x\), we will use the technique of substitution. Let's go through the steps in detail.
### Step 1: Identify the Integral
We need to evaluate:
\[
\int \sin 3x \, \mathrm{d}x
\]
### Step 2: Use Substitution
To simplify the integration, we can use a substitution. Let:
\[
u = 3x
\]
Then, we differentiate \(u\) with respect to \(x\):
\[
\frac{\mathrm{d}u}{\mathrm{d}x} = 3 \quad \Rightarrow \quad \mathrm{d}u = 3 \, \mathrm{d}x \quad \Rightarrow \quad \mathrm{d}x = \frac{1}{3} \mathrm{d}u
\]
### Step 3: Substitute in the Integral
Now, we can substitute \(u\) and \(\mathrm{d}x\) into the integral:
\[
\int \sin 3x \, \mathrm{d}x = \int \sin u \cdot \frac{1}{3} \mathrm{d}u = \frac{1}{3} \int \sin u \, \mathrm{d}u
\]
### Step 4: Integrate \(\sin u\)
The integral of \(\sin u\) is:
\[
\int \sin u \, \mathrm{d}u = -\cos u + C
\]
where \(C\) is the constant of integration.
### Step 5: Substitute Back
Now, we substitute back \(u = 3x\):
\[
\frac{1}{3} \int \sin u \, \mathrm{d}u = \frac{1}{3} (-\cos u + C) = -\frac{1}{3} \cos(3x) + C
\]
### Final Answer
Thus, the evaluated integral is:
\[
\int \sin 3x \, \mathrm{d}x = -\frac{1}{3} \cos(3x) + C
\]
### Conclusion
The correct option is:
**C. (-1/3) cos 3x + c**
### Explanation of Other Options
- **Option A: (2/3) cos 3x + c**
- This option is incorrect because it suggests a positive coefficient for \(\cos(3x)\), which contradicts the integral of \(\sin(3x)\) that results in a negative cosine function.
- **Option B: (1/3) cos 3x + c**
- This option is also incorrect for the same reason as option A. The integral of \(\sin(3x)\) should yield a negative cosine term, not a positive one.
- **Option D: (-2/3) cos 3x + c**
- This option is incorrect because it has the wrong coefficient. The correct coefficient is \(-\frac{1}{3}\), not \(-\frac{2}{3}\).
### Revision Summary
- Use substitution to simplify integrals involving trigonometric functions.
- Remember that the integral of \(\sin u\) is \(-\cos u + C\).
- Always substitute back to the original variable after integration.
- Check the signs and coefficients carefully when selecting the correct answer from multiple choices.