Question 849 of 949
A straight conductor carrying a current of 5 A is placed in a uniform magnetic field of strength 0.2 T. If the length of the conductor within the magnetic field is 0.3 m and the angle between the magnetic field and the current is 90 degrees, what is the magnetic force acting on the conductor?
Correct Answer:
C
Explanation
To determine the magnetic force acting on a straight conductor carrying a current in a magnetic field, we can use the formula:
\[
F = B \cdot I \cdot L \cdot \sin(\theta)
\]
Where:
- \( F \) is the magnetic force (in Newtons, N)
- \( B \) is the magnetic field strength (in Teslas, T)
- \( I \) is the current (in Amperes, A)
- \( L \) is the length of the conductor within the magnetic field (in meters, m)
- \( \theta \) is the angle between the magnetic field and the direction of the current (in degrees or radians)
### Given Data:
- Current, \( I = 5 \, \text{A} \)
- Magnetic field strength, \( B = 0.2 \, \text{T} \)
- Length of the conductor, \( L = 0.3 \, \text{m} \)
- Angle, \( \theta = 90^\circ \)
### Step-by-Step Calculation:
1. **Identify the sine of the angle**: Since the angle \( \theta \) is \( 90^\circ \), we know that:
\[
\sin(90^\circ) = 1
\]
2. **Substitute the values into the formula**:
\[
F = B \cdot I \cdot L \cdot \sin(\theta)
\]
\[
F = 0.2 \, \text{T} \cdot 5 \, \text{A} \cdot 0.3 \, \text{m} \cdot 1
\]
3. **Perform the multiplication**:
- First, calculate \( B \cdot I \):
\[
0.2 \, \text{T} \cdot 5 \, \text{A} = 1.0 \, \text{T} \cdot \text{A}
\]
- Next, multiply by \( L \):
\[
1.0 \, \text{T} \cdot \text{A} \cdot 0.3 \, \text{m} = 0.3 \, \text{N}
\]
4. **Final Result**:
\[
F = 0.3 \, \text{N}
\]
### Conclusion:
The magnetic force acting on the conductor is **0.3 N**. Therefore, the correct option is **A**.
### Explanation of Other Options:
- **Option B (0.6 N)**: This value could arise if the current or the length of the conductor were doubled, but with the given values, it does not apply.
- **Option C (0.9 N)**: This value is incorrect as it suggests a higher force than calculated. It could be a result of miscalculating the multiplication or misunderstanding the angle.
- **Option D (1.2 N)**: This option is also incorrect and would imply an even larger force, which is not supported by the given parameters.
### Common Pitfalls:
- **Forgetting the sine function**: Always remember to include the sine of the angle, especially if it is not \( 90^\circ \) or \( 0^\circ \).
- **Misreading units**: Ensure that all units are consistent (e.g., T for magnetic field, A for current, m for length).
- **Calculation errors**: Double-check each step of multiplication to avoid simple arithmetic mistakes.
### Revision Summary:
- Use the formula \( F = B \cdot I \cdot L \cdot \sin(\theta) \) to calculate magnetic force.
- Ensure to substitute the correct values and calculate step-by-step.
- Remember that \( \sin(90^\circ) = 1 \) simplifies the calculation.
- Check your final answer against the options provided to ensure accuracy.