Question 836 of 949
What is the formula for calculating the energy stored in a capacitor with capacitance \( C \) (in farads) charged to a voltage \( V \) (in volts)?
- \( \frac{1}{2} CV^2 \)
- \( CV \)
- \( \frac{1}{2} C^2V \)
- \( V^2/C \)
Correct Answer:
A
Explanation
The correct option for the formula for calculating the energy stored in a capacitor with capacitance \( C \) (in farads) charged to a voltage \( V \) (in volts) is **A. \( \frac{1}{2} CV^2 \)**.
### Detailed Explanation
1. **Understanding Capacitance**:
- A capacitor is a device that stores electrical energy in an electric field. The capacitance \( C \) of a capacitor is defined as the amount of charge \( Q \) it can store per unit voltage \( V \). This relationship is given by the formula:
\[
C = \frac{Q}{V}
\]
- Rearranging this gives us:
\[
Q = CV
\]
- This means that the charge stored in the capacitor is directly proportional to both the capacitance and the voltage across it.
2. **Energy Stored in a Capacitor**:
- The energy \( U \) stored in a capacitor can be derived from the work done to charge it. When charging a capacitor, the voltage across it increases as it accumulates charge. The work done to move a small amount of charge \( dq \) against the voltage \( V \) is given by:
\[
dU = V \, dq
\]
- Since the voltage \( V \) is not constant while charging, we need to express \( V \) in terms of \( q \):
\[
V = \frac{q}{C}
\]
- Substituting this into the work done gives:
\[
dU = \frac{q}{C} \, dq
\]
- To find the total energy stored, we integrate from \( 0 \) to \( Q \):
\[
U = \int_0^Q \frac{q}{C} \, dq
\]
- Performing the integration:
\[
U = \frac{1}{C} \int_0^Q q \, dq = \frac{1}{C} \left[ \frac{q^2}{2} \right]_0^Q = \frac{1}{C} \cdot \frac{Q^2}{2} = \frac{Q^2}{2C}
\]
- Now, substituting \( Q = CV \) into the equation:
\[
U = \frac{(CV)^2}{2C} = \frac{C V^2}{2}
\]
- Thus, the energy stored in a capacitor is:
\[
U = \frac{1}{2} CV^2
\]
### Why Other Options Are Incorrect
- **Option B: \( CV \)**:
- This formula represents the charge \( Q \) stored in the capacitor, not the energy. While it is true that \( Q = CV \), it does not account for the work done in charging the capacitor.
- **Option C: \( \frac{1}{2} C^2V \)**:
- This option is incorrect because it incorrectly combines the terms. The energy stored is not dependent on \( C^2 \) but rather on \( C \) and \( V^2 \). The correct relationship involves \( V^2 \) rather than \( C^2 \).
- **Option D: \( V^2/C \)**:
- This option is also incorrect. It suggests a relationship that does not correspond to the energy stored in a capacitor. The energy should be proportional to \( V^2 \) but divided by \( 2 \) and multiplied by \( C \), not divided by \( C \).
### Summary for Revision
- The energy stored in a capacitor is given by the formula \( U = \frac{1}{2} CV^2 \).
- Capacitance \( C \) relates charge \( Q \) and voltage \( V \) through \( Q = CV \).
- The work done to charge a capacitor is integrated to find the energy stored.
- Common pitfalls include confusing charge with energy and misapplying the relationships between \( C \), \( V \), and \( Q \).
This thorough understanding of the energy stored in a capacitor will help you in both theoretical and practical applications in physics.