Question 654 of 949
In a uniform electric field \( E \), what is the expression for the electric flux \( \Phi_E \) through a surface area \( A \) that is oriented at an angle \( \theta \) to the field direction?
- \( \Phi_E = E \cdot A \)
- \( \Phi_E = E \cdot A \cdot \cos(\theta) \)
Correct Answer:
D
Explanation
The correct option for the expression of electric flux \( \Phi_E \) through a surface area \( A \) that is oriented at an angle \( \theta \) to the electric field \( E \) is:
**D. \( \Phi_E = E \cdot A \cdot \cos(\theta) \)**
### Detailed Explanation
1. **Understanding Electric Flux**:
Electric flux \( \Phi_E \) is a measure of the quantity of electric field lines passing through a given surface. It is defined mathematically as:
\[
\Phi_E = \int \vec{E} \cdot d\vec{A}
\]
where \( \vec{E} \) is the electric field vector and \( d\vec{A} \) is the differential area vector on the surface. The dot product indicates that only the component of the electric field that is perpendicular to the surface contributes to the flux.
2. **Surface Orientation**:
When a surface is oriented at an angle \( \theta \) to the direction of the electric field, the effective area through which the electric field lines pass is reduced. The area vector \( d\vec{A} \) is perpendicular to the surface, and the angle \( \theta \) is the angle between the electric field vector \( \vec{E} \) and the area vector \( d\vec{A} \).
3. **Calculating the Flux**:
To find the electric flux through the surface, we can express the area vector in terms of the total area \( A \) and the angle \( \theta \):
\[
d\vec{A} = A \cdot \hat{n}
\]
where \( \hat{n} \) is the unit vector normal to the surface. The component of the electric field that contributes to the flux is \( E \cdot \cos(\theta) \), where \( E \) is the magnitude of the electric field.
Therefore, the electric flux can be calculated as:
\[
\Phi_E = E \cdot A \cdot \cos(\theta)
\]
### Why Other Options Are Incorrect
- **Option B: \( \Phi_E = E \cdot A \)**:
This option does not account for the angle \( \theta \). It assumes that the electric field is perpendicular to the surface, which is only true when \( \theta = 0^\circ \). In general, the flux must include the cosine factor to account for the angle of orientation.
- **Options A and C**:
Since these options are blank, they do not provide any expression for electric flux. Therefore, they cannot be correct.
### Common Pitfalls
- **Ignoring the Angle**: A common mistake is to forget to include the cosine factor when calculating electric flux, especially when the surface is not perpendicular to the electric field.
- **Confusing Area and Effective Area**: Students may confuse the total area \( A \) with the effective area through which the electric field lines pass. Remember, the effective area is reduced by the cosine of the angle.
### Revision Summary
- Electric flux \( \Phi_E \) is given by \( \Phi_E = E \cdot A \cdot \cos(\theta) \).
- The angle \( \theta \) is crucial as it determines how much of the electric field contributes to the flux through the surface.
- The dot product in the definition of electric flux accounts for the orientation of the surface relative to the electric field.
- Always remember to include the cosine factor when the surface is not perpendicular to the electric field.