Question 445 of 949
A car travels 150 meters to the east in 5 seconds. What is its average speed during this time interval?
- 25 m/s
- 30 m/s
- 15 m/s
- 20 m/s
Correct Answer:
D
Explanation
To determine the average speed of the car, we can use the formula for average speed, which is defined as the total distance traveled divided by the total time taken.
### Step-by-Step Explanation:
1. **Identify the Given Values**:
- Distance traveled (d) = 150 meters
- Time taken (t) = 5 seconds
2. **Use the Average Speed Formula**:
The formula for average speed (v) is:
\[
v = \frac{d}{t}
\]
where:
- \( v \) is the average speed,
- \( d \) is the distance traveled,
- \( t \) is the time taken.
3. **Substitute the Values into the Formula**:
Plugging in the values we have:
\[
v = \frac{150 \text{ meters}}{5 \text{ seconds}}
\]
4. **Perform the Calculation**:
Now, we perform the division:
\[
v = 30 \text{ m/s}
\]
5. **Conclusion**:
The average speed of the car during the 5 seconds is **30 m/s**.
### Explanation of the Correct Option:
- The correct answer is **B. 30 m/s**. This is because we calculated the average speed using the correct formula and substituted the correct values.
### Explanation of Why Other Options are Incorrect:
- **A. 25 m/s**: This option is incorrect because it does not match the calculated average speed. If we were to calculate the average speed to be 25 m/s, the distance would have to be \( 25 \text{ m/s} \times 5 \text{ s} = 125 \text{ meters} \), which is not the case here.
- **C. 15 m/s**: This option is also incorrect. If the average speed were 15 m/s, the distance would be \( 15 \text{ m/s} \times 5 \text{ s} = 75 \text{ meters} \), which is significantly less than the actual distance traveled.
- **D. 20 m/s**: This option is incorrect as well. If the average speed were 20 m/s, the distance would be \( 20 \text{ m/s} \times 5 \text{ s} = 100 \text{ meters} \), which again does not match the actual distance traveled.
### Common Pitfalls:
- **Confusing Speed with Velocity**: Remember that speed is a scalar quantity (only magnitude), while velocity is a vector quantity (magnitude and direction). In this problem, we are only concerned with speed.
- **Miscalculating Time or Distance**: Always double-check the values given in the problem to ensure they are used correctly in calculations.
### Revision Summary:
- Average speed is calculated using the formula \( v = \frac{d}{t} \).
- For this problem, the average speed is \( 30 \text{ m/s} \).
- Always ensure to use the correct values for distance and time.
- Be cautious of confusing average speed with average velocity, as they are different concepts.