Question 407 of 949
What is the gravitational field strength at a distance \( r \) from a point mass \( M \)?
- \( \frac{GM}{r^2} \)
- \( \frac{G}{Mr^2} \)
- \( \frac{M}{Gr^2} \)
- \( \frac{Gr^2}{M} \)
Correct Answer:
A
Explanation
### Correct Option: A. \( \frac{GM}{r^2} \)
#### Detailed Explanation:
1. **Understanding Gravitational Field Strength**:
- The gravitational field strength (\( g \)) at a point in space is defined as the force per unit mass experienced by a small test mass placed at that point. It is a vector quantity that points towards the mass creating the gravitational field.
2. **Newton's Law of Universal Gravitation**:
- According to Newton's law, the gravitational force (\( F \)) between two masses \( M \) (the point mass) and \( m \) (the test mass) separated by a distance \( r \) is given by:
\[
F = \frac{GMm}{r^2}
\]
- Here, \( G \) is the gravitational constant, approximately \( 6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \).
3. **Deriving Gravitational Field Strength**:
- To find the gravitational field strength \( g \) at a distance \( r \) from the mass \( M \), we can rearrange the formula for gravitational force:
\[
g = \frac{F}{m}
\]
- Substituting the expression for \( F \):
\[
g = \frac{GMm/r^2}{m}
\]
- The mass \( m \) cancels out:
\[
g = \frac{GM}{r^2}
\]
- This shows that the gravitational field strength at a distance \( r \) from a point mass \( M \) is indeed \( \frac{GM}{r^2} \).
4. **Why Option A is Correct**:
- Option A correctly represents the derived formula for gravitational field strength, confirming that it is directly proportional to the mass \( M \) and inversely proportional to the square of the distance \( r \).
#### Explanation of Other Options:
- **Option B: \( \frac{G}{Mr^2} \)**
- This option incorrectly places \( M \) in the denominator. The gravitational field strength should be proportional to the mass \( M \), not inversely. Thus, this option is incorrect.
- **Option C: \( \frac{M}{Gr^2} \)**
- Similar to option B, this option incorrectly suggests that \( G \) is in the denominator. The gravitational field strength should not have \( G \) in the denominator, making this option incorrect.
- **Option D: \( \frac{Gr^2}{M} \)**
- This option also misrepresents the relationship. It suggests that gravitational field strength increases with \( r^2 \) and decreases with \( M \), which contradicts the established relationship. Therefore, this option is incorrect.
### Summary of Key Points:
- The gravitational field strength \( g \) at a distance \( r \) from a point mass \( M \) is given by \( g = \frac{GM}{r^2} \).
- This formula is derived from Newton's law of universal gravitation.
- Gravitational field strength is directly proportional to the mass creating the field and inversely proportional to the square of the distance from the mass.
- Understanding the correct relationships in the formula is crucial for solving problems related to gravitational fields.