Question 5 of 949
A car of mass 800kg attains a speed of 25m/s in 20 secs. The power developed in the engine is
- A. 1 . 25 x 104 W
- B. 2 . 50 x 104 W
- C. 1 . 25 x 106W
- D. 2 . 50 x 106 W
Correct Answer:
A
Explanation
To determine the power developed in the engine of the car, we need to follow a series of steps involving the concepts of work, energy, and power in physics. Let's break it down step-by-step.
### Step 1: Calculate the Kinetic Energy (KE) of the Car
The kinetic energy of an object can be calculated using the formula:
\[
KE = \frac{1}{2} mv^2
\]
where:
- \( m \) is the mass of the object (in kilograms),
- \( v \) is the velocity of the object (in meters per second).
For the car:
- Mass \( m = 800 \, \text{kg} \)
- Speed \( v = 25 \, \text{m/s} \)
Substituting the values into the formula:
\[
KE = \frac{1}{2} \times 800 \, \text{kg} \times (25 \, \text{m/s})^2
\]
Calculating \( (25 \, \text{m/s})^2 \):
\[
(25 \, \text{m/s})^2 = 625 \, \text{m}^2/\text{s}^2
\]
Now substituting back into the kinetic energy formula:
\[
KE = \frac{1}{2} \times 800 \times 625
\]
\[
KE = 400 \times 625 = 250000 \, \text{J} \quad (\text{Joules})
\]
### Step 2: Calculate the Power Developed
Power is defined as the rate at which work is done or energy is transferred. The formula for power \( P \) is:
\[
P = \frac{W}{t}
\]
where:
- \( W \) is the work done (or energy transferred, in this case, the kinetic energy),
- \( t \) is the time taken (in seconds).
From our previous calculation, we found that the work done (or kinetic energy) is \( 250000 \, \text{J} \), and the time taken to reach this speed is \( 20 \, \text{s} \).
Substituting these values into the power formula:
\[
P = \frac{250000 \, \text{J}}{20 \, \text{s}} = 12500 \, \text{W}
\]
### Step 3: Convert Power to Kilowatts
Since power is often expressed in kilowatts (kW), we can convert watts to kilowatts by dividing by 1000:
\[
P = \frac{12500 \, \text{W}}{1000} = 12.5 \, \text{kW}
\]
### Step 4: Final Answer in Watts
To express this in standard form, we can write:
\[
P = 1.25 \times 10^4 \, \text{W}
\]
### Conclusion: Correct Option
The correct option is **A. 1.25 x 10^4 W**.
### Explanation of Other Options
- **B. 2.50 x 10^4 W**: This value is too high. It would imply that the car developed more power than calculated, which is not supported by the energy and time values given.
- **C. 1.25 x 10^6 W**: This is an order of magnitude too high. It suggests a power level that is unrealistic for a typical car engine in this scenario.
- **D. 2.50 x 10^6 W**: This is also significantly too high and would imply an extremely powerful engine, far beyond typical automotive applications.
### Revision Summary
- Kinetic energy is calculated using \( KE = \frac{1}{2} mv^2 \).
- Power is the rate of doing work, calculated as \( P = \frac{W}{t} \).
- The car's kinetic energy was found to be 250,000 J, leading to a power output of 12,500 W or 1.25 x 10^4 W.
- Always check units and conversions when calculating power and energy.