Question 317 of 949
A car accelerates uniformly from rest at a rate of 3 m/s². How far does the car travel in the first 5 seconds?
- 15 meters
- 30 meters
- 45 meters
- 75 meters
Correct Answer:
C
Explanation
To determine how far the car travels in the first 5 seconds while accelerating uniformly from rest at a rate of 3 m/s², we can use the equations of motion. Specifically, we will use the second equation of motion, which relates distance, initial velocity, acceleration, and time.
### Step-by-Step Explanation
1. **Identify the Variables**:
- Initial velocity (u): Since the car starts from rest, \( u = 0 \, \text{m/s} \).
- Acceleration (a): The car accelerates at \( a = 3 \, \text{m/s}^2 \).
- Time (t): We are interested in the distance traveled in \( t = 5 \, \text{s} \).
2. **Use the Equation of Motion**:
The equation that relates these variables is:
\[
s = ut + \frac{1}{2} a t^2
\]
where:
- \( s \) is the distance traveled,
- \( u \) is the initial velocity,
- \( a \) is the acceleration,
- \( t \) is the time.
3. **Substitute the Values**:
Plugging in the values we have:
\[
s = (0 \, \text{m/s}) \cdot (5 \, \text{s}) + \frac{1}{2} (3 \, \text{m/s}^2) (5 \, \text{s})^2
\]
4. **Calculate Each Term**:
- The first term \( (0 \, \text{m/s}) \cdot (5 \, \text{s}) = 0 \, \text{m} \).
- The second term:
\[
\frac{1}{2} (3 \, \text{m/s}^2) (5 \, \text{s})^2 = \frac{1}{2} (3) (25) = \frac{75}{2} = 37.5 \, \text{m}
\]
5. **Combine the Results**:
Since the first term is zero, the total distance \( s \) is:
\[
s = 0 + 37.5 \, \text{m} = 37.5 \, \text{m}
\]
### Conclusion
The distance traveled by the car in the first 5 seconds is **37.5 meters**. However, since this value does not match any of the provided options, it seems there may have been a misunderstanding in the options or the question itself.
### Analyzing the Options
- **A. 15 meters**: This is incorrect because it underestimates the distance based on the given acceleration and time.
- **B. 30 meters**: This is also incorrect; it is still less than the calculated distance.
- **C. 45 meters**: This is incorrect; it is slightly higher than the calculated distance.
- **D. 75 meters**: This is incorrect; it significantly overestimates the distance.
### Common Pitfalls
- **Misunderstanding the initial conditions**: Always ensure you correctly identify the initial velocity, especially if the object starts from rest.
- **Forgetting to square the time**: In the equation \( \frac{1}{2} a t^2 \), the time must be squared, which is a common mistake.
- **Not using the correct units**: Ensure that all units are consistent (e.g., meters, seconds).
### Revision Summary
- Use the equation of motion \( s = ut + \frac{1}{2} a t^2 \) to find distance.
- Substitute the correct values for initial velocity, acceleration, and time.
- Calculate each term carefully, especially squaring the time.
- Check your final answer against the options provided, and be aware of potential discrepancies.