Question 239 of 949
In a reverse biased junction diode, current flows in by
- A. positive holes alone
- B. majority carriers
- C. electron alone
- D. minority carriers
Correct Answer:
D
Explanation
### Correct Option: D. Minority carriers
### Detailed Explanation:
A reverse-biased junction diode is a semiconductor device that is designed to allow current to flow in one direction (forward bias) while blocking it in the opposite direction (reverse bias). In reverse bias, the p-n junction is connected such that the p-type material is connected to the negative terminal of the power supply and the n-type material is connected to the positive terminal. This setup widens the depletion region and prevents the majority carriers from crossing the junction.
#### Step-by-Step Breakdown:
1. **Understanding the Junction Diode**:
- A diode consists of two types of semiconductor materials: p-type (which has an abundance of holes, or positive charge carriers) and n-type (which has an abundance of electrons, or negative charge carriers).
- In a p-n junction, the p-type and n-type materials are brought together, creating a depletion region where electrons and holes recombine, leaving behind charged ions.
2. **Reverse Bias Condition**:
- When a diode is reverse-biased, the external voltage increases the width of the depletion region. This means that the barrier for charge carriers to cross the junction becomes larger.
- Majority carriers (holes in p-type and electrons in n-type) are pushed away from the junction, preventing them from contributing to current flow.
3. **Current Flow in Reverse Bias**:
- Despite the majority carriers being pushed away, there is still a small amount of current that can flow due to the presence of minority carriers.
- Minority carriers are the less abundant charge carriers in a semiconductor. In a p-type material, the minority carriers are electrons, and in an n-type material, the minority carriers are holes.
- In reverse bias, the minority carriers can still move across the junction. For example, electrons from the p-type region can drift into the n-type region, and holes from the n-type region can drift into the p-type region.
4. **Resulting Current**:
- The current that flows in a reverse-biased diode is primarily due to these minority carriers. This current is typically very small and is known as reverse saturation current.
- The reverse saturation current is temperature-dependent and increases with temperature due to increased thermal generation of electron-hole pairs.
### Why Other Options Are Incorrect:
- **Option A: Positive holes alone**:
- This option is incorrect because, in reverse bias, holes (the majority carriers in p-type material) are pushed away from the junction and do not contribute to current flow.
- **Option B: Majority carriers**:
- This option is incorrect because majority carriers are not able to cross the junction in reverse bias. They are repelled away from the junction, thus not contributing to the current.
- **Option C: Electrons alone**:
- This option is misleading. While electrons are indeed involved in the current flow, they are minority carriers in the p-type material. The statement does not account for the fact that holes (the minority carriers in n-type) also contribute to the current, albeit to a lesser extent.
### Summary of Key Points:
- In a reverse-biased junction diode, current flows due to minority carriers (electrons in p-type and holes in n-type).
- Majority carriers are repelled from the junction and do not contribute to current flow in reverse bias.
- The current in reverse bias is typically very small and is known as reverse saturation current.
- Understanding the behavior of minority carriers is crucial for analyzing diode operation in reverse bias.
This thorough understanding of how current flows in a reverse-biased junction diode is essential for mastering semiconductor physics and preparing for related exam questions.