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Question 31 of 480

The first term of a geometric progression is twice its common ratio. Find the sum of the first two terms of the G.P if its sum to infinity is 8.

  • A. 8/5
  • B. 8/3
  • C. 72/25
  • D. 56/9

Correct Answer: C

Explanation
To solve the problem, we need to analyze the information given about the geometric progression (G.P.) and use the properties of G.P.s to find the sum of the first two terms. ### Step 1: Understanding the Problem We are told that: - The first term of the G.P. is twice its common ratio. - The sum to infinity of the G.P. is 8. Let’s denote: - The first term as \( a \). - The common ratio as \( r \). From the problem statement, we can express the first term in terms of the common ratio: \[ a = 2r \] ### Step 2: Sum to Infinity of a Geometric Progression The formula for the sum to infinity \( S \) of a G.P. is given by: \[ S = \frac{a}{1 - r} \] This formula is valid only when the absolute value of the common ratio \( |r| < 1 \). Given that the sum to infinity is 8, we can set up the equation: \[ \frac{a}{1 - r} = 8 \] ### Step 3: Substitute the First Term Now, substituting \( a = 2r \) into the sum to infinity formula: \[ \frac{2r}{1 - r} = 8 \] ### Step 4: Solve for \( r \) To solve for \( r \), we can cross-multiply: \[ 2r = 8(1 - r) \] Expanding the right side: \[ 2r = 8 - 8r \] Now, we can combine like terms: \[ 2r + 8r = 8 \] \[ 10r = 8 \] Dividing both sides by 10: \[ r = \frac{8}{10} = \frac{4}{5} \] ### Step 5: Find the First Term \( a \) Now that we have \( r \), we can find \( a \): \[ a = 2r = 2 \times \frac{4}{5} = \frac{8}{5} \] ### Step 6: Calculate the Sum of the First Two Terms The first two terms of the G.P. are: - First term \( a = \frac{8}{5} \) - Second term \( ar = \frac{8}{5} \times \frac{4}{5} = \frac{32}{25} \) Now, we can find the sum of the first two terms: \[ \text{Sum of first two terms} = a + ar = \frac{8}{5} + \frac{32}{25} \] To add these fractions, we need a common denominator. The common denominator between 5 and 25 is 25: \[ \frac{8}{5} = \frac{8 \times 5}{5 \times 5} = \frac{40}{25} \] Now we can add: \[ \frac{40}{25} + \frac{32}{25} = \frac{40 + 32}{25} = \frac{72}{25} \] ### Conclusion: Final Answer Thus, the sum of the first two terms of the G.P. is: **C. \( \frac{72}{25} \)** ### Step 7: Explanation of Other Options - **Option A: \( \frac{8}{5} \)** - This is just the first term, not the sum of the first two terms. - **Option B: \( \frac{8}{3} \)** - This does not correspond to any calculation we performed and is not related to the sum of the first two terms. - **Option D: \( \frac{56}{9} \)** - This value does not match any of our calculations and is incorrect. ### Revision Summary - The first term \( a \) is twice the common ratio \( r \). - The sum to infinity of a G.P. is calculated using \( S = \frac{a}{1 - r} \). - We found \( r = \frac{4}{5} \) and \( a = \frac{8}{5} \). - The sum of the first two terms is \( \frac{72}{25} \).
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