Question 146 of 480
Find the coordinates of the mid-point of x and y intercepts of the line 2y = 4x - 8
- A. (2, 0)
- B. (1, -2)
- C. (-1, -2)
- D. (1, 2)
Correct Answer:
B
Explanation
To find the coordinates of the mid-point of the x and y intercepts of the line given by the equation \(2y = 4x - 8\), we will follow these steps:
### Step 1: Rewrite the Equation in Slope-Intercept Form
First, we need to rewrite the equation in a more familiar form, which is the slope-intercept form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.
Starting with the original equation:
\[
2y = 4x - 8
\]
We divide every term by 2 to isolate \(y\):
\[
y = 2x - 4
\]
### Step 2: Find the Y-Intercept
The y-intercept occurs where \(x = 0\). We can find it by substituting \(x = 0\) into the equation:
\[
y = 2(0) - 4 = -4
\]
Thus, the y-intercept is at the point \((0, -4)\).
### Step 3: Find the X-Intercept
The x-intercept occurs where \(y = 0\). We can find it by substituting \(y = 0\) into the equation:
\[
0 = 2x - 4
\]
Adding 4 to both sides gives:
\[
2x = 4
\]
Dividing by 2 results in:
\[
x = 2
\]
Thus, the x-intercept is at the point \((2, 0)\).
### Step 4: Find the Mid-Point of the Intercepts
Now that we have both intercepts:
- Y-intercept: \((0, -4)\)
- X-intercept: \((2, 0)\)
We can find the mid-point of these two points using the mid-point formula:
\[
\text{Mid-point} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
Substituting in our intercept coordinates:
\[
\text{Mid-point} = \left( \frac{0 + 2}{2}, \frac{-4 + 0}{2} \right) = \left( \frac{2}{2}, \frac{-4}{2} \right) = (1, -2)
\]
### Conclusion
The coordinates of the mid-point of the x and y intercepts of the line \(2y = 4x - 8\) are \((1, -2)\).
### Explanation of Options
- **Option A: (2, 0)** - This is the x-intercept, not the mid-point.
- **Option B: (1, -2)** - This is the correct answer, as calculated above.
- **Option C: (-1, -2)** - This point does not correspond to either intercept or the mid-point.
- **Option D: (1, 2)** - This point does not correspond to either intercept or the mid-point.
### Revision Summary
- The y-intercept is found by setting \(x = 0\) in the equation.
- The x-intercept is found by setting \(y = 0\) in the equation.
- The mid-point of two points is calculated using the mid-point formula.
- The correct mid-point of the intercepts for the line \(2y = 4x - 8\) is \((1, -2)\).