Question 107 of 480
If the gradient of the curve y = 2kx2 + x + 1 at x = 1 is 9, find k.
Correct Answer:
C
Explanation
To solve the problem, we need to find the value of \( k \) such that the gradient (or derivative) of the curve \( y = 2kx^2 + x + 1 \) at \( x = 1 \) equals 9. Let's break this down step-by-step.
### Step 1: Find the Derivative
The first step is to differentiate the function \( y \) with respect to \( x \). The function is:
\[
y = 2kx^2 + x + 1
\]
To find the derivative \( \frac{dy}{dx} \), we apply the power rule of differentiation, which states that if \( y = ax^n \), then \( \frac{dy}{dx} = nax^{n-1} \).
1. Differentiate \( 2kx^2 \):
- The derivative is \( 2k \cdot 2x^{2-1} = 4kx \).
2. Differentiate \( x \):
- The derivative is \( 1 \).
3. Differentiate \( 1 \):
- The derivative is \( 0 \) (since the derivative of a constant is zero).
Putting it all together, we have:
\[
\frac{dy}{dx} = 4kx + 1
\]
### Step 2: Evaluate the Derivative at \( x = 1 \)
Next, we need to evaluate the derivative at \( x = 1 \):
\[
\frac{dy}{dx} \bigg|_{x=1} = 4k(1) + 1 = 4k + 1
\]
### Step 3: Set the Derivative Equal to 9
According to the problem, the gradient at \( x = 1 \) is 9. Therefore, we set up the equation:
\[
4k + 1 = 9
\]
### Step 4: Solve for \( k \)
Now, we solve for \( k \):
1. Subtract 1 from both sides:
\[
4k = 9 - 1
\]
\[
4k = 8
\]
2. Divide both sides by 4:
\[
k = \frac{8}{4} = 2
\]
### Conclusion
Thus, the value of \( k \) is \( 2 \). Therefore, the correct option is:
**C. 2**
### Explanation of Other Options
- **A. 4**: If \( k = 4 \), then \( 4k + 1 = 4(4) + 1 = 16 + 1 = 17 \), which is not equal to 9.
- **B. 3**: If \( k = 3 \), then \( 4k + 1 = 4(3) + 1 = 12 + 1 = 13 \), which is also not equal to 9.
- **D. 1**: If \( k = 1 \), then \( 4k + 1 = 4(1) + 1 = 4 + 1 = 5 \), which again is not equal to 9.
### Revision Summary
- To find the gradient of a curve, differentiate the function with respect to \( x \).
- Evaluate the derivative at the specified point to find the gradient at that point.
- Set the evaluated derivative equal to the given gradient and solve for the unknown variable.
- Always check other options to confirm they do not satisfy the condition given in the problem.