Question 74 of 513
56.00cm3 of a gas at S.T.P. weighed 0.11g. What is the vapour density of the gas?
[Molar volume of a gas at S.T.P = 22.4dm3]
- A. 11.00
- B. 22.00
- C. 33.00
- D. 44.00
Correct Answer:
B
Explanation
To determine the vapor density of the gas, we need to follow a series of steps that involve understanding the relationship between mass, volume, and molar volume at standard temperature and pressure (S.T.P.).
### Step-by-Step Explanation
1. **Understanding Vapor Density**:
- Vapor density is defined as the mass of a certain volume of gas compared to the mass of an equal volume of hydrogen at the same temperature and pressure. It can also be calculated using the formula:
\[
\text{Vapor Density} = \frac{\text{Mass of gas}}{\text{Volume of gas at S.T.P.}}
\]
2. **Given Data**:
- Volume of gas = 56.00 cm³
- Mass of gas = 0.11 g
- Molar volume of a gas at S.T.P. = 22.4 dm³ (which is equivalent to 22,400 cm³)
3. **Convert Volume to dm³**:
- Since the molar volume is given in dm³, we need to convert the volume of the gas from cm³ to dm³:
\[
56.00 \, \text{cm}^3 = \frac{56.00}{1000} \, \text{dm}^3 = 0.056 \, \text{dm}^3
\]
4. **Calculate the Molar Mass of the Gas**:
- To find the vapor density, we first need to find the molar mass of the gas. The molar mass can be calculated using the formula:
\[
\text{Molar Mass} = \frac{\text{Mass of gas}}{\text{Volume of gas at S.T.P.}} \times \text{Molar Volume}
\]
- Plugging in the values:
\[
\text{Molar Mass} = \frac{0.11 \, \text{g}}{0.056 \, \text{dm}^3} \times 22.4 \, \text{dm}^3
\]
5. **Perform the Calculation**:
- First, calculate the mass per dm³:
\[
\frac{0.11 \, \text{g}}{0.056 \, \text{dm}^3} \approx 1.9643 \, \text{g/dm}^3
\]
- Now, multiply by the molar volume:
\[
\text{Molar Mass} \approx 1.9643 \, \text{g/dm}^3 \times 22.4 \, \text{dm}^3 \approx 44.00 \, \text{g/mol}
\]
6. **Calculate Vapor Density**:
- The vapor density is half of the molar mass (since vapor density is defined relative to hydrogen, which has a molar mass of 2 g/mol):
\[
\text{Vapor Density} = \frac{\text{Molar Mass}}{2} = \frac{44.00 \, \text{g/mol}}{2} = 22.00
\]
### Conclusion
The correct answer is **B. 22.00**.
### Explanation of Other Options:
- **A. 11.00**: This value is incorrect because it suggests a molar mass of 22 g/mol, which does not match our calculations.
- **C. 33.00**: This value is also incorrect as it implies a molar mass of 66 g/mol, which is not supported by the data provided.
- **D. 44.00**: While this is the molar mass we calculated, it is not the vapor density. The vapor density is half of the molar mass.
### Revision Summary:
- Vapor density is calculated using the mass of the gas and its volume at S.T.P.
- Convert volumes to the same units (dm³) when necessary.
- Molar mass can be derived from the mass and volume of the gas.
- Vapor density is half the molar mass when compared to hydrogen.