Question 296 of 513
In the reaction between hydrogen gas (H₂) and oxygen gas (O₂) to form water (H₂O), what is the balanced chemical equation, and what is the mole ratio of hydrogen to oxygen used in the reaction?
- 2 H₂ + O₂ → 2 H₂O; 1:1
- H₂ + O₂ → H₂O; 2:1
- 2 H₂ + O₂ → 2 H₂O; 2:1
- H₂ + O₂ → 2 H₂O; 1:2
Correct Answer:
C
Explanation
### Correct Option: C. 2 H₂ + O₂ → 2 H₂O; 2:1
### Detailed Explanation:
1. **Understanding the Reaction**:
The reaction between hydrogen gas (H₂) and oxygen gas (O₂) to form water (H₂O) is a fundamental chemical reaction known as combustion. In this reaction, hydrogen and oxygen combine to produce water.
2. **Writing the Unbalanced Equation**:
Initially, we can write the unbalanced equation as:
\[
\text{H}_2 + \text{O}_2 \rightarrow \text{H}_2\text{O}
\]
3. **Balancing the Equation**:
To balance the equation, we need to ensure that the number of atoms of each element on the reactant side (left) is equal to the number on the product side (right).
- **Counting Atoms**:
- On the left side:
- H: 2 (from H₂)
- O: 2 (from O₂)
- On the right side:
- H: 2 (from H₂O)
- O: 1 (from H₂O)
- **Balancing Oxygen**:
Since there are 2 oxygen atoms on the left and only 1 on the right, we need to adjust the number of water molecules produced. We can do this by placing a coefficient of 2 in front of H₂O:
\[
\text{H}_2 + \text{O}_2 \rightarrow 2 \text{H}_2\text{O}
\]
- **Recounting Atoms**:
Now, we have:
- On the left:
- H: 2
- O: 2
- On the right:
- H: 4 (from 2 H₂O)
- O: 2 (from 2 H₂O)
- **Balancing Hydrogen**:
To balance the hydrogen, we need 4 hydrogen atoms on the left. We can achieve this by placing a coefficient of 2 in front of H₂:
\[
2 \text{H}_2 + \text{O}_2 \rightarrow 2 \text{H}_2\text{O}
\]
- **Final Count**:
- Left:
- H: 4 (from 2 H₂)
- O: 2 (from O₂)
- Right:
- H: 4 (from 2 H₂O)
- O: 2 (from 2 H₂O)
Now, the equation is balanced.
4. **Mole Ratio**:
The balanced equation shows that for every 2 moles of hydrogen gas (H₂), 1 mole of oxygen gas (O₂) is required to produce 2 moles of water (H₂O). Therefore, the mole ratio of hydrogen to oxygen in this reaction is:
\[
\text{Mole ratio of H₂ to O₂} = 2:1
\]
### Why Other Options Are Incorrect:
- **Option A: 2 H₂ + O₂ → 2 H₂O; 1:1**
- This option correctly states the balanced equation but incorrectly states the mole ratio. The correct mole ratio is 2:1, not 1:1.
- **Option B: H₂ + O₂ → H₂O; 2:1**
- This option presents an unbalanced equation. The correct balanced equation is 2 H₂ + O₂ → 2 H₂O. Additionally, the mole ratio stated (2:1) is correct, but it is based on an incorrect equation.
- **Option D: H₂ + O₂ → 2 H₂O; 1:2**
- This option also presents an unbalanced equation. The correct balanced equation is 2 H₂ + O₂ → 2 H₂O. The mole ratio of 1:2 is incorrect; it should be 2:1.
### Revision Summary:
- The balanced chemical equation for the reaction of hydrogen and oxygen to form water is **2 H₂ + O₂ → 2 H₂O**.
- The mole ratio of hydrogen to oxygen in this reaction is **2:1**.
- Always ensure to balance chemical equations by counting the number of atoms of each element on both sides.
- Use coefficients to adjust the number of molecules in the reaction to achieve balance.