Use the BASIC program below to answer this question 10 LET K = 2 20 LET L = 9 30 LET SUM = 0 40 FOR J = K TO STEP 2 50 SUM = SUM + J2 60 PRINT "ANSWER =", SUM 70 NEXT J 80 END The last output that will be displayed by the program is

Question 161 of 319

Correct Answer: D

To determine the last output displayed by the BASIC program, let's analyze the code step by step. Step-by-Step Explanation

Initialization:
The program starts by initializing two variables:
- K is set to 2.
- L is set to 9.
It also initializes SUM to 0, which will be used to accumulate the results.
FOR Loop:
The FOR loop is defined as FOR J = K TO L STEP 2. This means:
- The loop starts with J equal to K (which is 2).
- It will continue to increment J by 2 until it reaches or exceeds L (which is 9).
The values of J during the iterations will be: 2, 4, 6, and 8.
Calculating the Sum:
Inside the loop, the program executes the line SUM = SUM + J2. However, it seems there is a typographical error in the code. The correct operation should be SUM = SUM + J^2 (where J^2 means J squared).
Let's calculate the value of SUM for each iteration:
- Iteration 1: When J = 2
- SUM = 0 + 2^2 = 0 + 4 = 4
- Iteration 2: When J = 4
- SUM = 4 + 4^2 = 4 + 16 = 20
- Iteration 3: When J = 6
- SUM = 20 + 6^2 = 20 + 36 = 56
- Iteration 4: When J = 8
- SUM = 56 + 8^2 = 56 + 64 = 120
End of Loop:
After the last iteration, J would increment to 10, which exceeds L (9), thus exiting the loop.
Output:
The program then executes the line PRINT "ANSWER =", SUM, which will display the final value of SUM, which is 120.

Conclusion The last output displayed by the program is 120. Explanation of Other Options

Option A: 20 - This value corresponds to the sum after the second iteration (when J is 4), but it does not account for the subsequent iterations.
Option B: 36 - This value does not match any of the calculated sums at any point in the iterations. It seems to be a miscalculation.
Option C: 64 - This value could be confused with the square of 8, but it does not represent the accumulated sum at any point in the program.
Option D: 120 - This is the correct answer, as calculated through the iterations.

Revision Summary

The program initializes variables and uses a FOR loop to iterate through even numbers from 2 to 8.
The sum of squares of these numbers is calculated and stored in SUM.
The final output is printed after all iterations are complete.
The correct answer is 120, as it is the accumulated sum of squares of 2, 4, 6, and 8.