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Geometry Concepts

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Geometry Concepts


1. Pythagoras Theorem, Sine Rule, and Cosine Rule

1.1 Pythagoras Theorem

Definition

In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

c2=a2+b2c^2 = a^2 + b^2

Where:

Example

A triangle has sides 3cm3 \, \text{cm} and 4cm4 \, \text{cm}, and the hypotenuse is unknown.

c2=32+42=9+16=25c^2 = 3^2 + 4^2 = 9 + 16 = 25 c=25=5cmc = \sqrt{25} = 5 \, \text{cm}

Applications


1.2 Sine Rule

Formula

For any triangle:

asinA=bsinB=csinC\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}

Where:

Example

Given A=30,B=60,a=10cmA = 30^\circ, B = 60^\circ, a = 10 \, \text{cm}, find bb.

asinA=bsinB\frac{a}{\sin A} = \frac{b}{\sin B} 10sin30=bsin60\frac{10}{\sin 30^\circ} = \frac{b}{\sin 60^\circ} 100.5=b0.866\frac{10}{0.5} = \frac{b}{0.866} b=17.32cmb = 17.32 \, \text{cm}

1.3 Cosine Rule

Formula

For any triangle:

c2=a2+b22abcosCc^2 = a^2 + b^2 - 2ab \cos C

Where:

Example

Given a=7cm,b=10cm,C=60a = 7 \, \text{cm}, b = 10 \, \text{cm}, C = 60^\circ, find cc:

c2=72+1022(7)(10)cos60c^2 = 7^2 + 10^2 - 2(7)(10)\cos 60^\circ c2=49+10070c^2 = 49 + 100 - 70 c2=79,c=798.89cmc^2 = 79, \, c = \sqrt{79} \approx 8.89 \, \text{cm}

Applications


2. Lengths of Arcs, Perimeters of Sectors, and Segments

2.1 Length of an Arc

Formula

Arc Length=θ×r\text{Arc Length} = \theta \times r

Where:

Example

A circle has a radius of 7cm7 \, \text{cm}, and θ=π3\theta = \frac{\pi}{3}:

Arc Length=π3×7=7π37.33cm\text{Arc Length} = \frac{\pi}{3} \times 7 = \frac{7\pi}{3} \approx 7.33 \, \text{cm}

2.2 Perimeter of a Sector

Formula

Perimeter=2r+Arc Length\text{Perimeter} = 2r + \text{Arc Length}

Example

Using the previous arc length (7.33cm7.33 \, \text{cm}) and r=7cmr = 7 \, \text{cm}:

Perimeter=2(7)+7.33=14+7.33=21.33cm\text{Perimeter} = 2(7) + 7.33 = 14 + 7.33 = 21.33 \, \text{cm}

2.3 Segment of a Circle

A segment is the area between a chord and an arc.

Area=12r2(θsinθ)\text{Area} = \frac{1}{2}r^2(\theta - \sin \theta)

Example

For a radius of 7cm7 \, \text{cm} and θ=π3\theta = \frac{\pi}{3}:

Area=12(7)2(π3sinπ3)\text{Area} = \frac{1}{2}(7)^2\left(\frac{\pi}{3} - \sin\frac{\pi}{3}\right)

3. Longitudes and Latitudes

3.1 Definition

3.2 Distance Between Two Points

Formula

Distance=R×Δθ\text{Distance} = R \times \Delta\theta

Where:

Example

Two points have a latitude difference of 3030^\circ:

Δθ=30×π180=π6\Delta\theta = \frac{30 \times \pi}{180} = \frac{\pi}{6} Distance=6371×π63336km\text{Distance} = 6371 \times \frac{\pi}{6} \approx 3336 \, \text{km}

3.3 Real-World Applications

  1. Navigation: Calculating shortest flight routes.
  2. Geography: Measuring distance between cities.
  3. Astronomy: Locating celestial bodies.

3.4 Common Misconceptions


4. Summary

These concepts are foundational in navigation, astronomy, engineering, and practical problem-solving in everyday life.